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EclipsesInvestigateabout 35 min

Build it, test it, try to break it

A lamp-and-balls model, hands-on measurements, and predictions checked against real eclipses

Hands-on layer: build a scale model of the Earth-Moon-Sun system, test the new-moon/full-moon rule and the shadow-width formula for yourself, find the tilt's hidden threshold, build a pinhole projector and check its numbers, and plan around three real upcoming eclipses.

Start at chapter 1

In this part you’ll

  • Build a scale model of the Earth-Moon system with a lamp and two balls, and compute the model's Sun size and distance.
  • Test the claim that eclipses need new or full moon using the moon-phase lab, and explain why other phases fail.
  • Measure and predict shadow widths using width = blocker width × screen distance ÷ blocker distance.
  • Use the eclipse-lab and a tilt table to find the threshold tilt below which the eclipse count would not change.
  • Build a pinhole projector, measure its image size, and check the measurement against the 9.3 mm-per-metre rule.

Discover told you what an eclipse is. Understand gave you the geometry. Now it is your turn to build it, test it and try to break it.

This layer is full of things to actually do: a lamp-and-balls model you can build on a table, labs where you drag the Moon around and read off numbers, and predictions you should make before you check the answer, not after.

The plan: build a scale model, test whether eclipses really do need new or full moon, measure shadow cones for yourself, find out whether the tilt is really doing all the work, and check the arithmetic behind the safety rules by making your own pinhole projector.

Need a different angle?

Running a fair test in any of the labs below

  1. Step 01Predict firstbefore

    Write down what you expect to happen, and why, before touching any slider.

  2. Step 02Change one thingone variable

    Move only the slider named in the instructions. Leave everything else exactly where it was.

  3. Step 03Read off the resultmeasure

    Note the number the lab reports — a width, a percentage, a count — not just a general impression.

  4. Step 04Reset, then change the other thingone at a time

    Put the first slider back before touching a second one, so you always know which change caused which result.

  5. Step 05Compare with the worked examplecheck

    If your reading and the worked example disagree by more than a rounding error, look for what you changed by accident.

Chapter 01

Three quick predictions

Predict first

You shine a torch at a 4 cm ball held 20 cm from the torch, with a screen 60 cm from the torch. The shadow on the screen is 12 cm wide (check: 4 × 60 ÷ 20 = 12). If you slide the ball to 40 cm from the torch, keeping the screen at 60 cm, what happens to the shadow?

Predict first

The Moon takes 29.53 days to go from new moon to new moon, and Earth's shadow is enormous. If the Moon's orbit had no tilt at all, how many solar eclipses would a year contain?

Predict first

You point a pinhole card at the Sun and make an image on paper 1 metre away: it comes out about 9 mm across. If you move the paper to 3 metres away, roughly how big is the image, and is it brighter, dimmer or the same?

Chapter 02

Build it: a lamp and two balls

You do not need a planetarium to make a real eclipse. You need a lamp, two balls of different sizes, and a metre or two of floor space.

What you need: a bright torch or a bare bulb lamp (the Sun), a small ball about 2 cm across such as a large bead or a marble (the Moon), a bigger ball about 7 cm across such as an orange or a tennis ball (Earth), and a dark room.

What to do:

  1. Set the lamp at one end of the room. This is the Sun. Do not move it again.
  2. Hold the big ball (Earth) about 2 metres from the lamp.
  3. Hold the small ball (Moon) between the lamp and Earth, about 6 cm from Earth's surface — close, the way the real Moon is close compared with the Sun.
  4. Look at Earth's surface, on the side facing the small ball. Can you see a tiny dark spot? That is your model solar eclipse — the Moon's shadow landing on Earth.
  5. Now move the small ball to the far side of Earth, in Earth's own shadow. Its surface should darken. That is your model lunar eclipse.
Need a different angle?

Worked example

0 / 5 steps shown

Getting the model's proportions right

If your Moon-ball is 2 cm across, how big should the Earth-ball be, and how far apart should they stand, to keep the same proportions as the real Earth–Moon system? (Moon = 3,475 km across, Earth = 12,742 km across, distance = 384,400 km.)

Need a different angle?

Lab

Recreate the lamp-and-balls model on screen and find the distance where the small ball's shadow just reaches the big one.

0250 cmLamp2 cm Moon-ballscreen5.3 cm
How many times taller2.67×
Shadow height5.3 cm

2 cm Moon-ball, 2 cm tall, stands 75 cm from the lamp. The screen is 2 m from the lamp, which is 2.67 times further, so the shadow is 2.67 times taller: 5.3 cm. The lamp is a tiny point, so the shadow has a sharp edge.

A tiny lamp makes a sharp shadow. Every ray starts from one point, so the edge of the shadow is one clean line. Look at the two yellow rays: the lamp, the top of the 2 cm moon-ball and the top of the shadow all sit on one straight line. That is what makes the two triangles the same shape.

Drag the round handles on the bench, or use the sliders — or focus a handle and press the arrow keys (hold Shift for big jumps). The picture is drawn to scale.

Round 1 / 2★ 0 ptsBest: 0

Shadow challenges: move the lamp, object and screen until the shadow is exactly the size asked for. Anything within 5% counts.

Model: light travels in perfectly straight lines and the object is a flat card facing the lamp. Real shadows are also softened a little by light bouncing off walls and floors.

Text version of this activity

A lamp, a small ball and a large ball on a virtual table, matching the tabletop version: 2 cm Moon-ball, 7 cm Earth-ball, point source lamp.

Slide the Moon-ball back and forth. Close to the lamp, its shadow cone is long and reaches well past the Earth-ball — like the real Moon's shadow arriving with room to spare at perigee. Slide it further from the lamp and the cone shortens until its tip lands exactly on the Earth-ball's surface, and a little further still, the tip falls short and a bright rim shows around the dark centre — your tabletop version of an annular eclipse.

Use this to connect the model in your hands with the numbers in the worked example: the real Moon's shadow cone is about 374,000 km long and its distance is about 384,400 km, a much closer call than the model usually shows unless you place things carefully.

Need a different angle?

Chapter 03

Test it: does an eclipse really need new or full moon?

Understand told you a solar eclipse needs new moon and a lunar eclipse needs full moon. Do not take that on trust — test it.

The Moon runs through eight named phases in one 29.53-day cycle: new, waxing crescent, first quarter, waxing gibbous, full, waning gibbous, last quarter, waning crescent, and back to new. At each phase, ask: is the Moon between Earth and the Sun, behind Earth, or off to one side?

TableTesting every phase: can an eclipse happen there?
PhaseWhere the Moon isSolar eclipse possible?Lunar eclipse possible?
New moonBetween Earth and SunYes, if also near a nodeNo — wrong side of Earth
Waxing crescentA quarter-turn from newNo — nowhere near the Sun–Earth lineNo
First quarterSide-on to the SunNoNo
Waxing gibbousApproaching fullNoNo
Full moonBehind Earth from the SunNo — wrong side entirelyYes, if also near a node
Waning gibbousPast fullNoNo
Last quarterSide-on, other sideNoNo
Waning crescentApproaching newNoNo

Lab

Step the Moon through a full month and check the claim: only new moon lines up for a solar eclipse and only full moon lines up for a lunar eclipse.

SunEarththe Moon is always half lit — we just see it from the sidenot to scale: distances and sizes are squashed to fitrises 6:00 amhighest 12:00 pmsets 6:00 pmas seen from India
PhaseNew moon
Lit up0%
Rises about6:00 am

Up in the sky: Up all day with the Sun, and lost in its glare. New moon is the one night you cannot see the Moon at all. Sets about 6:00 pm.

The Sun lights exactly half the Moon, all month long. What changes is where we are standing to look at it. Day 0.0 means the Moon is 0° round its orbit from new moon.

Text version of this activity

A dual view: the Moon orbiting Earth as seen from above (from-space), and what its lit shape looks like from Earth (from-earth), both driven by the same day-of-month slider from 0 to 29.5.

Step through slowly and watch the from-space view. Only at day 0 (new moon) does the Moon sit on the Sun side of Earth, roughly in line with the Sun. Only at day ≈14.8 (full moon) does it sit on the far side, roughly in line with Earth's shadow. At every other day it is off to one side, and no shadow from either body can reach the other.

This confirms the rule from Understand: the phase condition is not a coincidence added on top of the geometry, it is the geometry, seen from a different angle.

Need a different angle?

Predict first

Could a "solar eclipse" ever happen at first quarter, when the Moon is exactly half-lit as seen from Earth?

Try it

It is new moon today, so the Moon is roughly between Earth and the Sun. Is a solar eclipse guaranteed?

Chapter 04

Measure it: the shadow-width rule

Now put numbers on what you have been watching. A shadow behind a small, close blocker with a point light source obeys one simple rule:

shadow width = blocker width × (screen distance ÷ blocker distance)

Use the lab to measure real values, then check them against the practice problems below.

Try it

cm

Try it

cm

Try it

cm

Lab

Move a ball between a point lamp and a screen, read off the shadow width, and check it against the ball width × screen distance ÷ ball distance rule.

0200 cmLamp4 cm ballscreen10.7 cm
How many times taller2.67×
Shadow height10.7 cm

4 cm ball, 4 cm tall, stands 60 cm from the lamp. The screen is 1.6 m from the lamp, which is 2.67 times further, so the shadow is 2.67 times taller: 10.7 cm. The lamp is a tiny point, so the shadow has a sharp edge.

A tiny lamp makes a sharp shadow. Every ray starts from one point, so the edge of the shadow is one clean line. Look at the two yellow rays: the lamp, the top of the 4 cm ball and the top of the shadow all sit on one straight line. That is what makes the two triangles the same shape.

Drag the round handles on the bench, or use the sliders — or focus a handle and press the arrow keys (hold Shift for big jumps). The picture is drawn to scale.

Round 1 / 2★ 0 ptsBest: 0

Shadow challenges: move the lamp, object and screen until the shadow is exactly the size asked for. Anything within 5% counts.

Model: light travels in perfectly straight lines and the object is a flat card facing the lamp. Real shadows are also softened a little by light bouncing off walls and floors.

Text version of this activity

A lamp, a movable ball with a choice of two widths, and a screen with a ruler along it, reporting the shadow's exact width as you drag.

Try the three practice problems above in the lab before or after solving them on paper: set the ball to 4 cm, put it 20 cm from the lamp with the screen at 60 cm, and check the readout says 12 cm. Then try 30 cm and 40 cm and watch the shadow shrink each time.

A ratio readout also shows shadow width ÷ ball width, which is the same as screen distance ÷ ball distance — useful for the two challenges above.

Need a different angle?

Chapter 05

Investigate: total, annular, or nothing at all?

Set up an eclipse-lab experiment: fix the Sun and Earth, and change only the Moon's distance and its offset from the Sun–Earth line. Before every run, write down a prediction.

Need a different angle?

Lab

Change only the Moon's distance and offset, one at a time, and record whether you get total, annular, partial or nothing.

SunMoonEarthTotal eclipseSizes are right; the gaps between them are squashed about 100× to fit

Total eclipse

The Moon covers the Sun completely. For a few minutes the sky goes dark enough to see stars, birds go quiet, and the Sun’s pearly outer atmosphere — the corona — appears around a black disc.

Moon looks0.569°

Sun looks 0.533° wide

Totality strip225 km

out of 12,742 km across

The Moon's dark shadow is only 374 thousand km long, and the Moon is between 357 and 407 thousand km away. Sometimes the point of the cone reaches us and sometimes it stops just short — which is the whole difference between a total eclipse and a ring of fire.

Read this before you go outside

Never look at a partial solar eclipse — not for a second, not through sunglasses, smoked glass, an X-ray film or a phone camera. Use certified eclipse glasses or watch a pinhole projection on the ground. The Sun can burn the back of your eye without any pain to warn you.

Eclipses India has watched
  • 22 July 2009 · Total solar eclipse — Darkness swept from Surat across Indore, Bhopal, Varanasi and Patna — the longest total eclipse of this century.
  • 15 January 2010 · Annular solar eclipse — A ring of fire over Dhanushkodi and Rameswaram, Tamil Nadu, for over 10 minutes.
  • 26 December 2019 · Annular solar eclipse — The ring passed over Cheruvathur in Kerala and Coimbatore and Ooty in Tamil Nadu.
  • 7 September 2025 · Total lunar eclipse — A red Moon, visible from every part of India, with no glasses needed.
  • 2 August 2027 · Partial solar eclipse — Seen as a bite out of the Sun from western India; total over North Africa.
Text version of this activity

The same solar-eclipse model as before, but treated as an experiment: change the Moon's distance slider and note the result, then reset the distance and change the offset slider instead, and note that result too.

Suggested runs: (1) offset = 0, distance = perigee — expect the umbra to reach the ground; (2) offset = 0, distance = apogee — expect the antumbra and a ring; (3) offset = 0, distance = mean — expect a very thin ring; (4) offset = small, distance = perigee — expect the black spot to slide off the globe while the grey penumbra still clips it, giving a partial eclipse for a wider area; (5) offset = large — expect nothing at all.

Keep a simple table as you go: distance, offset, result. That table is the evidence behind every rule in Understand — you are re-deriving it instead of reading it.

Need a different angle?
TableA results matrix worth filling in yourself as you run the five suggested trials
Moon distanceOffset from the linePredictionWhat the lab actually shows
Perigee (363,300 km)0 (centred)Umbra reaches groundTotal — black disc, corona visible
Apogee (405,500 km)0 (centred)Umbra falls shortAnnular — bright ring, ≈18% of area left
Mean (384,400 km)0 (centred)Only just falls shortA very thin ring — barely annular
PerigeeSmall (a few thousand km)Umbra clips the edge of EarthPartial for a wide area; total only along a thin, curved track
Any distanceLarge (tens of thousands of km)Both cones miss Earth entirelyNothing — an ordinary new moon

Try it

%

Predict first

In a hybrid eclipse, the same event is total in the middle of its path and annular at both ends. What is different about the ends of the path compared with the middle?

Chapter 06

Investigate: how rare is it to stand in the path?

You now know the umbra's footprint is a spot only about 160 km wide. Before you do the arithmetic, predict: out of every 1,000 people scattered randomly over Earth's surface, roughly how many would you expect to be standing in the path of totality during any one total solar eclipse?

Need a different angle?

Worked example

0 / 5 steps shown

What share of Earth does one totality path cover?

Model the path of totality as a strip 160 km wide and about 10,000 km long (a generous, typical length). Earth's surface area is 4 × π × 6,371² km². What percentage of Earth's surface does the path cover?

Need a different angle?
Path width
≈160 kmTypical width of the umbra's footprint on the ground.
Path share of Earth
≈0.31%One path, modelled as 160 × 10,000 km, against Earth's full surface.
Total eclipses somewhere
≈68 per centuryAbout one total solar eclipse every 18 months on average, somewhere on Earth.
Wait for one fixed spot
≈375 yearsThe average time between two total eclipses crossing the very same place.

Predict first

Two friends argue. One says "total eclipses must be incredibly rare — I might never see one." The other says "they're not rare at all — one happens most years." Using the numbers above, whose claim is closer to being useful advice for planning a trip?

Worked example

0 / 4 steps shown

How long does the shadow take to cross a path?

A particular eclipse's path of totality runs about 4,800 km across the surface, and the shadow moves at roughly 2,000 km/h relative to the ground near the equator. Roughly how long does the whole event take to sweep from one end of the path to the other — and how does that compare with how long totality lasts at any one point?

Need a different angle?

Chapter 07

Investigate: how much does the tilt matter?

Understand explained why the real 5.145° tilt makes eclipses rare. Now run the experiment yourself and see how sensitive the answer is: does a little less tilt make a little more difference, or a lot?

TableThe node window at different tilts, and how much of the whole orbit counts (both nodes)
TiltWindow around each nodeShare of the whole orbit
0.0°360° — the whole orbit100% — every new moon and every full moon gives an eclipse
0.5°360° — still the whole orbit100% — a tilt below about 1.475° cannot keep the Moon out of range at all
1.0°360° — still the whole orbit100% — the required separation (1.475°) is still bigger than the tilt itself
2.0°≈95°≈53% — now the tilt is bigger than the separation limit, and gaps start to open up
5.145°≈33°≈18.5% — the real value, split between the two nodes
10.0°≈17°≈9.4% — double the real tilt roughly halves the share again

Lab

Drag the tilt slider through the values in the table and check the counter against your own predictions.

the flat planenodenodeEarthToo far above or below — the shadow missesThe tilt is drawn about 10× too big so you can see it at all
Off the plane by5.15°
That is34,472 km

34,472 km off the plane is 2.7 whole Earths' worth of miss. The shadow sails harmlessly over the top (or under the bottom) of us. Only within about 17° of a node is the line-up good enough — which happens in two short "eclipse seasons" a year, not every month.

The Moon's orbit is tilted 5.1° against the flat plane Earth goes round the Sun in. Two tilted circles can only cross at two points, and those two points are called the nodes. An eclipse needs a new or full moon to land almost exactly on a node.

Sizes on the picture: the Sun is 6,96,000 km in radius and 150 million km away, the Moon 1,737 km and about 3,84,400 km away. Their apparent sizes agree to within a few per cent — 0.52° against 0.53° — which is a coincidence, and the reason total solar eclipses exist at all.

Text version of this activity

The same why-not-monthly lab as before, used here to test the table above directly: set the tilt to each value in turn (0°, 0.5°, 1°, 2°, 5.145°, 10°) and note how many eclipses per year the counter reports.

The pattern to look for: nothing changes at all between 0° and about 1°, because the tilt is still smaller than the 1.475° separation the Moon needs to clear. Only once the tilt passes that threshold does raising it start cutting the eclipse count down — and it keeps cutting hard as the tilt grows further.

Need a different angle?

Reflect

This stays on this page only. It isn’t saved or sent anywhere.

Chapter 08

Test your eyes safely: build a pinhole projector

What you need: two pieces of stiff card, a pin, and a sunny day (a total eclipse is not required — a pinhole always makes an image of the Sun, eclipsed or not).

  1. Make one small, clean pinhole in the centre of the first card.
  2. Stand with your back to the Sun. Hold the pinhole card up so sunlight passes through the hole.
  3. Hold the second card as a screen, some distance behind the first, and find the bright disc of light.
  4. Measure the disc's width with a ruler, and measure the distance between the two cards.
  5. Move the screen further away and measure again.

Worked example

0 / 3 steps shown

Checking your own measurement against the formula

The Sun's angular width is 0.533°, so a pinhole makes an image about 9.3 mm across for every metre of distance to the screen. You measure your own projector at a screen distance of 2 metres and get an image 19 mm across. Is that close to the prediction?

Need a different angle?

Try it

mm

Chapter 09

Test your predictions against real eclipses

The best test of anything you have learned is a real eclipse on a real date. Three are already on the calendar for India.

TableThree eclipses to plan around
DateKindWhere in IndiaWhat you should predict beforehand
31 Dec 2028Total lunarFully visible across the whole countryRoughly what time totality starts, and how dark (Danjon score) it might look
21 May 2031Annular solarPath crosses Kerala, north Sri Lanka, the Andaman & Nicobar IslandsWhat percentage of the Sun will be covered where you live, if you are outside the path
20 Mar 2034Total solarPath of totality crosses northern India, including KashmirWhether your town is inside the path, and if not, how much partial coverage to expect
31 Dec 2028
833 daysAbout 2.3 years from today (20 Sep 2026).
21 May 2031
1,704 daysAbout 4.7 years away.
20 Mar 2034
2,738 daysAbout 7.5 years away — you would be about seven years older.

Reflect

This stays on this page only. It isn’t saved or sent anywhere.

Predict first

The path of totality for 20 March 2034 crosses northern India. If your town is 400 km south of that path, what would you expect to see?

Chapter 10

Wrap-up

w = b × s ÷ d
Shadow width w from a point source: blocker width b, screen distance s, blocker distance d.
image (mm) ≈ 9.31 × distance (m)
Pinhole image size, from the Sun's 0.533° angular width.
share = path area ÷ Earth area
Fraction of Earth's surface covered by one totality path, about 0.31%.
time = path length ÷ shadow speed
How long the shadow takes to sweep a path: hours for the whole path, minutes for one spot.

Helps you understand

Gravity

The Moon's elliptical orbit, which decides whether an eclipse is total or annular, is shaped by gravity.

Lab

Connect five experiments from this layer to the finding each one produced.

Match each test you ran to what it showed.

5 pairs are hiding in two mixed-up columns. Pick one from each side to join them.

Text version of this activity

A matching game pairing five hands-on tests with their results: the lamp-and-balls model showing the Sun cannot fit to scale in a room; the moon-phase lab confirming only new and full moon line up; shadow measurements confirming the width formula; the tilt slider revealing a hidden threshold near 1.475°; and the pinhole projector confirming the 9.3 mm-per-metre growth rate.

Words from this layer's tests

Point source
A light source small enough that its rays fan out from one spot, giving shadows with sharp edges.
Example: A bare, tiny bulb or a distant torch behaves like one.
Extended source
A light source with real width, so different edges of it are blocked at different places, giving a soft penumbra.
Example: The Sun is a large extended source, half a degree wide.
Scale model
A model where every real distance and size is shrunk by the same factor.
Example: A 2 cm Moon-ball needs a 7.3 cm Earth-ball 221 cm away to stay to scale.
Projection
Forming an image of a light source without looking at it directly, by letting its light fall on a screen.
Example: A pinhole, a colander, and gaps between leaves all work by projection.
Path of totality
The narrow track on Earth's surface where a total solar eclipse's umbra actually lands.
Example: About 160 km wide and roughly 0.31% of Earth's whole surface.
Threshold
A value below which changing something makes no difference, and above which it starts to matter.
Example: The 1.475° separation limit is a threshold for the Moon's tilt.

Quick check

Check what you found

9 questions · answer what you can, then check. Getting one wrong is useful.

  1. Q1A 6 cm ball sits 30 cm from a point lamp; the screen is 90 cm from the lamp. How wide is the shadow?
  2. Q2In the phase test, which two phases allow any kind of eclipse at all?
  3. Q3Why can a lamp-and-balls model not show the Sun at true scale in an ordinary room?
  4. Q4In the tilt experiment, why did the eclipse count stay at 24 a year for tilts of 0.5° and 1°?
  5. Q5Using 9.31 mm of image per metre, what image size would you predict at a screen distance of 0.5 m?
  6. Q6In the total-or-annular experiment, which single change turns a total eclipse into an annular one, all else being equal?
  7. Q7What makes a hybrid eclipse total in the middle of its track but annular at the ends?
  8. Q8One totality path covers about 0.31% of Earth's surface. What does that best explain?
  9. Q9A town 400 km outside the 2034 path of totality — what should residents prepare for?

Keep this

Cheat sheet

  • Shadow-width rule (point source): width = blocker width × screen distance ÷ blocker distance. Move the blocker away from the light and the shadow shrinks.
  • Lamp-and-balls model: a 2 cm Moon-ball needs a 7.3 cm Earth-ball about 2.2 m away to keep true proportions — but the Sun, at the same scale, would be an 8 m sphere 861 m off. The model shows the idea, not the true scale.
  • Phase test: only new moon (solar) and full moon (lunar) ever bring the three bodies near a line. Every other phase fails by tens of degrees, tilt or no tilt.
  • Tilt has a threshold near 1.475°. Below it, eclipses would happen every month regardless of the exact tilt. Above it, every extra degree of tilt cuts the eclipse-possible window hard. The real 5.145° is well past that threshold.
  • Pinhole image size: about 9.3 mm of image for every metre of screen distance, and dimmer the further you go. A bigger hole makes a bigger but blurrier, less crescent-shaped image — move the screen back instead.
  • Three real eclipses to test yourself against: 31 Dec 2028 (total lunar, all of India), 21 May 2031 (annular, Kerala/Sri Lanka/Andaman & Nicobar), 20 Mar 2034 (total, path across northern India including Kashmir).
  • SAFETY, always: every activity here projects an image onto paper. Never look at the Sun directly, with or without home-made equipment.

Where this comes from

Sources

End of Investigate

What you just read

  • Build a scale model of the Earth-Moon system with a lamp and two balls, and compute the model's Sun size and distance.
  • Test the claim that eclipses need new or full moon using the moon-phase lab, and explain why other phases fail.
  • Measure and predict shadow widths using width = blocker width × screen distance ÷ blocker distance.
  • Use the eclipse-lab and a tilt table to find the threshold tilt below which the eclipse count would not change.
  • Build a pinhole projector, measure its image size, and check the measurement against the 9.3 mm-per-metre rule.

The web

Explore a connection

  • Builds onanother area

    Light

    An eclipse is a shadow, and shadows need light that travels in straight lines.

  • Builds onanother area

    Gravity

    Eclipses happen only because the Sun, Earth and Moon move on fixed gravitational paths we can predict.

  • Builds on

    Phases of the Moon

    Eclipses can only happen at new moon or full moon — the two phases where the three bodies line up.

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Revision 1 · release preview-7e1cbbcc4f · accepted 20/09/2026