Skip to content

ElectricityInvestigateabout 40 min

Circuits you can test

Fair tests, meters, series and parallel, Ohm's law, fuses and fruit batteries

Design fair circuit tests, place ammeters and voltmeters correctly, compare series and parallel bulbs, test Ohm's law and see a filament bulb break it, work out when an MCB trips, and build a safe lemon battery.

Start at chapter 1

In this part you’ll

  • Plan a fair circuit investigation with independent, dependent and control variables, repeat readings and an uncertainty estimate.
  • Connect ammeters in series and voltmeters across components, and read meters and scales safely and honestly.
  • Predict and test current, voltage and brightness in series and parallel circuits, and explain why homes are wired in parallel.
  • Use a V–I table to decide whether a component is ohmic, and explain why a filament bulb is not.
  • Add appliance currents to predict overloads and explain what fuses, MCBs and short circuits do.

Up to now electricity may have felt like something to believe: invisible charge, invisible pushes, invisible resistance. This layer is where you stop believing and start testing. Every idea here can be checked with a battery, a few bulbs, some wire and a cheap multimeter — or with the labs on this page when you do not have the kit to hand.

You will learn to set up a fair test, to put meters in the right places, to read them honestly, and to decide whether your results really support a claim. Then you will use those skills on the big practical questions: why are the lights in your home wired in parallel? Does a bulb obey Ohm's law? What exactly makes an MCB trip when someone plugs a heater into an already-busy extension board? And can a lemon really power anything?

Two rules run through every chapter.

  1. Predict before you test. Write down what you expect and why. A surprise is only useful if you had an expectation to be surprised against.
  2. Low voltage only. Every hands-on activity here uses cells or batteries of 9 V or less. Mains electricity (230 V in India) appears only as calculations and simulations. The physics is the same; the danger is not.

Chapter 01

Designing a fair test with circuits

Suppose a friend claims: "A longer wire makes the bulb dimmer." How would you find out?

The tempting method is to grab a long wire and a short wire, connect each to a bulb, and compare. But if the long wire is thinner, or the battery was fresher for the first test, or you used a different bulb, you cannot tell which change caused the difference. A fair test changes exactly one thing on purpose and keeps everything else the same.

Scientists name the three kinds of variable:

  • Independent variable — the one thing you deliberately change (wire length).
  • Dependent variable — the thing you measure to see the effect (current through the bulb, or its brightness).
  • Control variables — everything else that could affect the result, which you hold steady (battery, bulb, wire thickness, wire material, temperature).
Need a different angle?
TablePlanning table: does wire length affect the current?
Kind of variableIn this testHow you handle it
IndependentLength of nichrome wire (10, 20, 30, 40, 50 cm)Move a crocodile clip along a wire taped to a metre rule
DependentCurrent through the circuitRead an ammeter connected in series
ControlBattery voltageUse the same 4.5 V battery pack; check it with a voltmeter before and after
ControlWire thickness and materialUse one single piece of the same wire for every length
ControlTemperature of the wireSwitch off between readings so the wire does not heat up and change its resistance

Why repeat readings? Any single reading can be thrown off: a loose crocodile clip, a meter that has not settled, a finger pressing a contact. Take each reading at least three times. If the repeats agree closely, you can trust them. If one is far from the others, it is an anomaly — check the circuit, find the cause if you can, and repeat that reading rather than quietly including it.

Why several values of the independent variable? Two lengths only tell you whether something changes. Five or six lengths, evenly spread, show you the pattern: does the current halve when the length doubles? Is the graph a straight line or a curve? Patterns are what turn a result into an explanation.

Predict first

In the wire-length investigation, the current is 0.60 A with 20 cm of nichrome wire in the circuit. The rest of the circuit has very little resistance. What do you predict at 40 cm?

Chapter 02

Measuring: meters, scales and uncertainty

Two meters do almost all the work in circuit investigations, and they are connected in opposite ways.

An ammeter measures current, the flow of charge through something. To count what flows through a bulb, the charge must flow through the meter too, so the ammeter goes in series: you break the circuit and let the meter become part of the loop. A good ammeter has a very low resistance so it barely changes the current it is measuring.

A voltmeter measures voltage (potential difference), the energy each coulomb of charge gains or loses between two points. So it connects across a component, in parallel, with one lead on each side. A good voltmeter has a very high resistance so almost no current is diverted through it.

In the water picture: an ammeter is a flow meter spliced into the pipe; a voltmeter is a pressure gauge with one tube before the pump or narrow pipe and one tube after it.

Need a different angle?
Ammeter
in seriesMeasures current in amperes (A). Very low resistance. Break the loop and insert it.
Voltmeter
acrossMeasures potential difference in volts (V). Very high resistance. Clip it on either side of the part.
Multimeter
bothOne box, a dial and three or four sockets. The dial and the red lead socket must match what you measure.
Typical bench
≤ 9 VCells and batteries only. Currents usually well under 1 A.

Using a multimeter safely on a battery circuit

  1. Step 01Choose the quantitydial

    Turn the dial to V⎓ (DC volts) for voltage or A⎓ / mA⎓ for current. Never measure with the dial on Ω while the circuit is powered.

  2. Step 02Choose the socketsleads

    Black lead in COM. Red lead in the V socket for voltage, the mA or A socket for current. The 10 A socket is often unfused — avoid it on small circuits.

  3. Step 03Start on a high rangerange

    If your meter is not auto-ranging, start on a higher range (20 V, 200 mA) and step down for more digits. Too low a range shows 1 or OL (over limit).

  4. Step 04Connect, then switch oncircuit

    Build the circuit with the switch open, check the meter position, then close the switch and read.

  5. Step 05Read and recorddata

    Wait for the digits to settle. Write the value with its unit and the number of digits the meter shows.

  6. Step 06Put it back to voltshabit

    Move the red lead back to V and turn the meter off. The next person who measures voltage with the lead in the A socket will short the battery.

Reading an analogue scale. Older school meters have a needle. First work out what each small division is worth: if the scale goes from 0 to 1 A with 50 divisions, each is 0.02 A. Read with your eye directly above the needle — looking from the side makes the needle appear to sit over a different mark (this is called parallax). If the needle sits between two marks, estimate to about half a division.

Reading a digital display. Digital meters feel exact, but the last digit can flicker. A reading of 0.46 A usually means "somewhere around 0.455 to 0.465 A", and the meter's own accuracy (printed in the manual, often something like ±1% plus a digit or two) adds more. The resolution is the smallest change the display can show: 0.01 A here.

Uncertainty is an honest statement of how far off your answer might be. A simple, widely used estimate is half the range of your repeat readings.

Worked example

0 / 5 steps shown

Mean and uncertainty from repeat readings

You measure the current through a resistor four times and get 0.46 A, 0.44 A, 0.62 A and 0.47 A. What should you record?

Need a different angle?

Chapter 03

Series circuits on the bench

A series circuit is a single loop. Charge leaves the battery, goes through the first bulb, then the second, then back — one path, no choices.

That single path has two consequences you can test. First, the current is the same everywhere in the loop: an ammeter placed before the first bulb, between the bulbs or after the last one shows the same reading. Charge is not used up by bulbs; it is energy that is transferred. Second, the battery's voltage is shared between the bulbs. With identical bulbs it is shared equally.

Predict first

A 6 V battery lights one bulb brightly. You add a second identical bulb in series. What happens?

Lab

Measure how current, bulb voltage and brightness change as identical bulbs are added in series, and what happens when one breaks.

2 bulb(s) in series share 6 V (3 V each). The same 250 mA flows through every bulb.6 V25%25%
Bulbs2
Battery current250 mA
Each bulb0.75 W

2 bulb(s) in series share 6 V (3 V each). The same 250 mA flows through every bulb.

Model: identical bulbs of fixed 12 Ω and an ideal 6 V battery.

Text version of this activity

The lab shows a 6 V battery and identical 12 Ω bulbs in a single loop. Results for 1 to 4 bulbs:

  • 1 bulb: total resistance 12 Ω, current 6 ÷ 12 = 0.50 A, bulb voltage 6 V, bulb power 3.0 W.
  • 2 bulbs: 24 Ω, current 0.25 A, each bulb 3 V and 0.75 W.
  • 3 bulbs: 36 Ω, current ≈ 0.17 A, each bulb 2 V and ≈ 0.33 W.
  • 4 bulbs: 48 Ω, current 0.125 A, each bulb 1.5 V and ≈ 0.19 W.

The current is the same at every point in the loop, the bulb voltages always add up to 6 V, and every added bulb makes all of them dimmer. If you break any one bulb, the only path is cut: the current everywhere becomes 0 A and every bulb goes out.

Need a different angle?
TableSeries results (6 V battery, identical 12 Ω bulbs, model values)
BulbsTotal resistanceCurrentVoltage per bulbPower per bulb
112 Ω0.50 A6.0 V3.0 W
224 Ω0.25 A3.0 V0.75 W
336 Ω0.17 A2.0 V0.33 W
448 Ω0.125 A1.5 V0.19 W
4, one brokenopen circuit0 A0 V0 W

Chapter 04

Parallel circuits on the bench

In a parallel circuit each bulb has its own branch, connected directly across the battery. Charge reaching a junction can go one way or the other, and the branches join again before returning to the battery.

Now the rules flip. Every branch gets the full battery voltage, so each bulb glows as brightly as a single bulb would. The branch currents add up to give the total current drawn from the battery. And because each branch is a separate path, breaking one bulb leaves the others working.

Predict first

A 6 V battery lights one bulb. You add a second identical bulb in parallel. What happens to the current drawn from the battery?

Lab

Measure branch current, total current and brightness as identical bulbs are added in parallel, and test what happens when one breaks.

2 bulb(s) in parallel each get the full 6 V and 500 mA; the battery supplies 1 A in total.6 V100%100%
Bulbs2
Battery current1 A
Each bulb3 W

2 bulb(s) in parallel each get the full 6 V and 500 mA; the battery supplies 1 A in total.

Model: identical bulbs of fixed 12 Ω and an ideal 6 V battery.

Text version of this activity

The lab shows a 6 V battery with identical 12 Ω bulbs, each on its own branch. Every bulb has 6 V across it, carries 6 ÷ 12 = 0.50 A and uses 3.0 W, however many bulbs there are. The total current is 0.50 A × the number of working bulbs: 0.50 A for one, 1.0 A for two, 1.5 A for three, 2.0 A for four. The total resistance falls: 12 Ω, 6 Ω, 4 Ω and 3 Ω. If you break one bulb, only its branch stops; the others stay exactly as bright and the total current drops by 0.50 A.

Need a different angle?
TableParallel results (6 V battery, identical 12 Ω bulbs, model values)
BulbsTotal resistanceCurrent per bulbTotal currentPower per bulb
112 Ω0.50 A0.50 A3.0 W
26 Ω0.50 A1.0 A3.0 W
34 Ω0.50 A1.5 A3.0 W
43 Ω0.50 A2.0 A3.0 W
4, one broken4 Ω0.50 A (3 working)1.5 A3.0 W (0 W in the broken one)

Predict first

Same battery, same three bulbs. Arrangement X has them in series; arrangement Y in parallel. Which battery goes flat first?

Lab

Switch the same three bulbs between series and parallel and compare brightness, battery current and the effect of a broken bulb.

3 bulb(s) in series share 9 V (3 V each). The same 167 mA flows through every bulb.9 V11%11%11%
Bulbs3
Battery current167 mA
Each bulb0.5 W

3 bulb(s) in series share 9 V (3 V each). The same 167 mA flows through every bulb.

Model: identical bulbs of fixed 18 Ω and an ideal 9 V battery.

Text version of this activity

This lab uses a 9 V battery and three identical 18 Ω bulbs, and lets you switch arrangements.

  • Series: total resistance 54 Ω, current 9 ÷ 54 ≈ 0.17 A, each bulb 3 V and 0.5 W; total power 1.5 W. One broken bulb puts all three out.
  • Parallel: each bulb 9 V, 0.50 A and 4.5 W; total current 1.5 A and total power 13.5 W, nine times the series total. One broken bulb leaves the other two fully bright and the total current falls to 1.0 A.

So parallel wins on brightness and reliability; series draws far less from the battery.

Need a different angle?

Chapter 05

Why homes are wired in parallel

Every socket, fan point and light point in your home is connected in parallel across the live and neutral wires that come from the meter and MCB board. Put the bench results next to what a home needs and the reason is obvious:

  • Every appliance gets the full 230 V. A 1500 W geyser is designed to work at 230 V. In series with a fan and a TV it would get only a share of the voltage and barely warm the water.
  • Each appliance can be switched independently. Turning off the bedroom light should not turn off the fridge. In series, one open switch would break the only loop and switch everything off.
  • One failure does not black out the house. A burnt-out tube light breaks its own branch only.
  • Adding an appliance does not dim the others. Each branch draws its own current at 230 V.

The price, as the bench showed, is that the currents add up in the shared wires. That is the whole reason fuses and MCBs exist, and it is the subject of Chapter 8.

Explore

What if a home were wired differently?

Pick a wiring plan for a room with a light, a fan and a phone charger.

  1. One loop
  2. Voltage shared three ways
  3. Every device under-powered
  4. One switch off → all off

Useless for a home

With 230 V shared between a 10 W LED light, a 60 W fan and a charger, none gets the voltage it was designed for. The fan would hardly turn, and turning off the light (opening the loop) would stop everything. Series is used deliberately only where a shared current is wanted — like old strings of tiny decorative lamps.

TableSeries versus parallel: the bench results side by side
QuestionSeriesParallel
Voltage across each bulbShared: adds up to the supplyFull supply voltage on every branch
CurrentSame everywhere in the loopBranch currents add up to the total
Adding a bulbAll bulbs get dimmer; total current fallsOthers unchanged; total current rises
One bulb breaksEverything goes outOnly that branch goes out
Total resistanceGoes up with every bulbGoes down with every branch
Where you see itSwitch and its load; old decorative light strings; cells in a torchEvery socket and light point in a home

Chapter 06

Ohm's law: the fixed-resistor experiment

Ohm's law says that for some conductors, current is proportional to voltage: double the voltage, double the current. The ratio V ÷ I is then constant, and we call that constant the resistance, R.

That is a claim about the world, so let us test it. The classic method uses a fixed resistor (say one marked 10 Ω), a variable supply or a battery pack you can change from 1.5 V to 9 V in 1.5 V steps, an ammeter in series and a voltmeter across the resistor.

  • Independent variable: voltage across the resistor.
  • Dependent variable: current through it.
  • Controls: the same resistor, kept at room temperature (switch off between readings), same leads and meters.
V = I × R
Voltage (V) equals current (A) times resistance (Ω).
I = V ÷ R
Rearranged to predict the current from a known voltage and resistance.
R = V ÷ I
Rearranged to work out resistance from a pair of meter readings.
P = V × I
Power in watts: how fast energy is transferred.

Predict first

With the 10 Ω resistor, 3.0 V gives a current of 0.30 A. What do you predict at 6.0 V?

Lab

Collect a table of voltage and current for a fixed resistor, check that current is proportional to voltage, and calculate R for each pair.

Current I = V ÷ R0.3 A
Power P = V × I0.9 W

3 V pushing through 10 Ω drives 0.3 A, turning 0.9 W into heat and light.

Model: fixed resistance (real bulb filaments change resistance as they heat).

Text version of this activity

The lab applies a chosen voltage (0.5 to 9 V) across a chosen fixed resistance (1 to 100 Ω) and shows the current I = V ÷ R. With R fixed at 10 Ω the readings are: 1.5 V → 0.15 A, 3.0 V → 0.30 A, 4.5 V → 0.45 A, 6.0 V → 0.60 A, 7.5 V → 0.75 A and 9.0 V → 0.90 A. Every pair gives V ÷ I = 10 Ω, and a graph of current against voltage is a straight line through the origin whose steepness is 1 ÷ R. Swapping to 47 Ω at 9 V gives 9 ÷ 47 ≈ 0.19 A: a bigger resistance gives a less steep line. The lab's resistance never changes with temperature, which is why its results are perfectly proportional.

Need a different angle?
TableA real set of results for a resistor marked 10 Ω (one reading per voltage, meters to 0.01)
Voltage (V)Current (A)R = V ÷ I (Ω)
1.50.1510.0
3.00.2910.3
4.50.469.8
6.00.6010.0
7.50.7410.1
9.00.919.9

Worked example

0 / 6 steps shown

Is the resistor ohmic? Analysing the table

Use the six results above to decide whether current is proportional to voltage and to estimate the resistance.

Need a different angle?

Chapter 07

The bulb that breaks the rule

Now repeat the experiment with a small filament bulb instead of a resistor — say a 6 V, 0.5 A torch bulb. At first the numbers look familiar. Then something odd happens: doubling the voltage does not double the current. The current keeps rising, but more and more slowly.

Calculate V ÷ I for each row and the reason jumps out: the bulb's resistance is not constant. It climbs as the voltage goes up.

TableTypical readings for a 6 V, 0.5 A filament torch bulb (illustrative values)
Voltage (V)Current (A)R = V ÷ I (Ω)What you see
0.50.202.5No glow; filament barely warm
1.00.263.8Faint red
2.00.345.9Dull orange
3.00.407.5Yellowish
4.00.449.1Bright
6.00.5012.0Full brightness

The filament is a very thin coil of tungsten wire. As more current flows it gets hotter — at full brightness a filament runs at well over 2000 °C. In a hot metal the atoms vibrate harder, so the drifting electrons collide with them more often, and the resistance rises. Between cold and white-hot, a tungsten filament's resistance typically rises by a factor of roughly 10 to 15.

So a filament bulb is non-ohmic. Its I–V graph starts steep near the origin (low, cold resistance) and bends over as it gets hotter (high resistance). The fixed resistor's graph was straight because it stayed at roughly room temperature.

Need a different angle?
TableCold versus hot filament resistance (hot values from R = V² ÷ P; cold values approximate)
BulbHot resistance (lit)Cold resistance (approx.)Ratio
6 V, 0.5 A torch bulb12 Ωabout 1 Ωabout 12×
60 W, 230 V household bulb230² ÷ 60 ≈ 880 Ωabout 60 Ωabout 15×
100 W, 230 V household bulb230² ÷ 100 ≈ 530 Ωabout 35–40 Ωabout 14×
100 W, 120 V bulb (USA)120² ÷ 100 = 144 Ωabout 9.5 Ωabout 15×

Chapter 08

Fuses, MCBs and overloads

Parallel wiring means the currents of everything switched on in a circuit add up in the wires they share. Those wires are sized to carry a certain current safely. Push more than that through them and, by P = I²R, they heat up — slowly at first, then enough to soften insulation and start a fire.

A fuse is a deliberately weak link: a short, thin wire that melts when the current exceeds its rating, breaking the circuit before the house wiring overheats. A miniature circuit breaker (MCB) does the same job but can be reset. It has two trip mechanisms: a bimetal strip that heats and bends on a moderate overload (tripping after seconds or minutes) and an electromagnet that snaps it open almost instantly on a huge current, such as a short circuit.

In many Indian homes, lighting and fan circuits are protected by 6 A or 10 A MCBs, and power circuits for sockets, geysers and ACs by 16 A or larger ones (the exact sizes depend on the wiring and the electrician's design).

Lab

Simulate appliances on a 230 V circuit protected by a 16 A MCB and find which combinations make it trip.

Current I = V ÷ R4.34 A
Power P = V × I998.1 W

230 V pushing through 53 Ω drives 4.34 A, turning 998.1 W into heat and light.

Protection rating: 16 A. Model: fixed resistance (real bulb filaments change as they heat).

Text version of this activity

This is a simulation only: never experiment with mains. The lab applies 230 V across a load and compares the current with a 16 A protective device. Each appliance is modelled as a resistance: a 1000 W iron is 230² ÷ 1000 ≈ 52.9 Ω and draws about 4.3 A; a 2000 W kettle or heater is ≈ 26.5 Ω and draws about 8.7 A. Several appliances in parallel act like one smaller resistance. Kettle + iron ≈ 17.6 Ω draws about 13 A — under 16 A, so the MCB holds. Kettle + iron + heater ≈ 10.6 Ω draws about 21.7 A — over 16 A, so the MCB trips. Lower resistance means more current; adding appliances in parallel always lowers the total resistance.

Need a different angle?

Worked example

0 / 8 steps shown

One extension board, three appliances

On a winter morning someone plugs a 2000 W kettle, a 1000 W iron and a 2000 W room heater into one extension board, on a socket circuit protected by a 16 A MCB. The supply is 230 V. Will the MCB trip?

Need a different angle?
Rewirable fuse
meltsThin fuse wire in a ceramic carrier. Cheap, but easily replaced with the wrong wire.
Cartridge fuse
meltsSealed element with a printed rating, e.g. inside some plugs, adaptors and appliances.
MCB
tripsThermal trip for overloads, magnetic trip for short circuits. Resettable with a switch.
RCCB / RCD
leakTrips on a small leakage to earth (often 30 mA) — protects people, not wires. Covered in the safety layers.

Chapter 09

Short circuits

A short circuit is a path with almost no resistance connected across a supply, so the current takes the short cut and skips the components it was meant to go through. Because I = V ÷ R and R is tiny, the current becomes enormous — limited only by the resistance of the wires and the supply itself.

On the bench, a short circuit is a bare wire accidentally touching both terminals of a battery. In a home, it is a live wire touching neutral inside a damaged cable or appliance. The mains supply can deliver hundreds or even thousands of amps for a moment, which is why the MCB's magnetic trip exists: it opens the circuit in a few thousandths of a second.

Predict first

Two bulbs are in series with a battery and both glow. You clip a thick copper wire across bulb B only, from one of its terminals to the other. What happens?

Worked example

0 / 5 steps shown

How big is a short-circuit current?

An AA cell (1.5 V) is accidentally shorted by a piece of wire with 0.05 Ω resistance. The cell's own internal resistance is about 0.15 Ω. Estimate the current and compare it with a torch bulb's normal current of about 0.3 A.

Chapter 10

Lemon and potato cells

A battery cell needs three things: two different metals and an electrolyte between them, a liquid or paste that can carry charge as ions. A lemon's acidic juice or a potato's watery flesh can be the electrolyte. Push in a strip of zinc (a galvanised iron nail is coated in zinc) and a piece of copper (a copper wire or strip), and a chemical reaction at the zinc releases electrons that flow through an outside wire to the copper.

The fruit is not the source of the energy — the zinc is, as it slowly dissolves. The fruit is the electrolyte that lets the reaction happen. A typical lemon cell with zinc and copper gives about 0.9 V, and a current of at most around 1 mA. That is thousands of times too little for a torch bulb, but a red LED needs only about 1.8–2 V and a few milliamps to glow faintly — so several fruit cells in series can light one, dimly, in a dark room.

Home investigation: build a lemon or potato battery

  1. Step 01Gather the kitmaterials

    4 lemons or potatoes, 4 galvanised (zinc-coated) nails, 4 pieces of thick copper wire or copper strip, 5 crocodile-clip leads, a multimeter, a red LED.

  2. Step 02Soften and preparesetup

    Roll each lemon on the table to free the juice. Push a nail and a copper piece into each, about 2 cm apart and 2–3 cm deep, not touching.

  3. Step 03Measure one cellmeasure

    Multimeter on DC volts (2 V or 20 V range). Red lead to copper, black to zinc. Record the voltage. Repeat three times, moving the clips off and on.

  4. Step 04Build a series chainseries

    Clip the copper of lemon 1 to the zinc of lemon 2, and so on. Measure the total voltage across the free ends after adding each lemon.

  5. Step 05Light the LEDtest

    Connect the chain to the LED: longer LED leg to the copper end. Look in a dark room. No glow? Flip the LED round; LEDs work one way only.

  6. Step 06Change one variablefair test

    Now test one factor: fruit type, electrode gap, depth or electrode size. Keep everything else the same and take repeat readings.

  7. Step 07Clean upsafety

    Throw the fruit away afterwards — do not eat it, because metal from the nails has dissolved into it. Wash your hands.

TableWhat to expect from lemon cells in series (typical values; yours will vary)
Cells in seriesExpected voltageCan it light a red LED?
1about 0.9 VNo — below the ~1.8 V the LED needs
2about 1.8 VMaybe, very faintly
3about 2.7 VUsually a faint glow in the dark
4about 3.6 VA clearer glow; current still only about 1 mA

Predict first

You cut a lemon in half and use just one half as the cell, with the same electrodes, gap and depth. What happens to the voltage?

Chapter 11

Batteries in series and in parallel

The fruit chain showed that cells in series add their voltages: each cell lifts the energy of every coulomb a little more, like pumps stacked one after another. That is why a TV remote uses two 1.5 V AA cells for 3 V, and why a rectangular 9 V battery is six small 1.5 V cells stacked inside one case.

Cells in parallel keep the same voltage as one cell but share the job of supplying current. With two identical cells side by side, each supplies half the current, so the pair can deliver more current and lasts roughly twice as long. Power banks and electric vehicle battery packs use both tricks: groups in parallel for capacity, groups in series for voltage.

TableCombining identical 1.5 V cells
ArrangementTotal voltageWhat changesEveryday example
1 cell1.5 VWall clock
2 in series3.0 VDouble the voltageTV remote, many torches
4 in series6.0 VFour times the voltageToys, some bicycle lights
2 in parallel1.5 VSame voltage, about twice the capacitySome solar garden lights, battery packs
3 in series, 1 reversed1.5 VThe reversed cell cancels one otherA torch put together carelessly

Predict first

A torch takes four 1.5 V cells in series. Someone puts one in the wrong way round. What voltage does the bulb get?

Worked example

0 / 5 steps shown

Designing a pack for a 6 V motor

A school project needs a small 6 V motor to run for as long as possible. You have eight AA cells (1.5 V each). How should you arrange them?

Quick check

Check your investigation skills

10 questions · answer what you can, then check. Getting one wrong is useful.

  1. Q1You test whether the number of lemons in series affects the voltage. Which of these is a control variable?
  2. Q2How should an ammeter be connected to measure the current through a bulb?
  3. Q3Three identical bulbs are in series with a battery. One filament breaks. What happens?
  4. Q4Four identical bulbs are in parallel across 6 V. Each bulb draws 0.5 A. What current flows from the battery?
  5. Q5What is the main reason homes are wired in parallel?
  6. Q6A component gives 2.0 V → 0.20 A, 4.0 V → 0.40 A and 8.0 V → 0.80 A. What can you conclude?
  7. Q7A 60 W, 230 V filament bulb has a resistance of about 880 Ω when lit. Measured cold with a multimeter, its resistance will be…
  8. Q8A 2000 W kettle and a 2000 W heater run on the same 230 V circuit. Roughly what total current flows?
  9. Q9Each lemon cell gives about 0.9 V. How many in series are needed to reach at least the ~1.8 V a red LED needs?
  10. Q10Two 1.5 V cells are in series but one is reversed. What is the total voltage?

Keep this

Cheat sheet

  • Fair test: change one independent variable, measure one dependent variable, keep every control variable the same. Take at least three repeats and several evenly spread values.
  • Ammeter in series (very low resistance); voltmeter across the part (very high resistance). Never put an ammeter across a battery.
  • Multimeter habits: right dial, right socket, start on a high range, and put the red lead back in V when finished. Never use it on mains.
  • Uncertainty ≈ half the range of your repeats. Remove an anomaly only when it is clearly out of line, then repeat that reading.
  • Series: one loop, same current everywhere, voltage shared, adding bulbs dims them all, one break turns everything off.
  • Parallel: full voltage on every branch, branch currents add, adding bulbs raises the total current, one break affects only its branch.
  • Homes are parallel so each appliance gets 230 V and its own switch. Each switch is in series with its own load.
  • Ohm's law: for an ohmic conductor at constant temperature, I is proportional to V and R = V ÷ I is constant. The I–V graph is a straight line through the origin.
  • Filament bulbs are non-ohmic: the hot filament has roughly 10–15 times its cold resistance, so the I–V graph bends over.
  • Overload: add the currents (I = P ÷ V). Kettle 8.7 A + iron 4.35 A + heater 8.7 A ≈ 21.7 A, which trips a 16 A MCB.
  • Fuse melts; MCB trips (thermal for overloads, magnetic for short circuits). Never bypass either.
  • Short circuit: a near-zero-resistance path; the current is limited only by wires and the supply's internal resistance.
  • Fruit cells: zinc + copper + electrolyte ≈ 0.9 V and up to about 1 mA per lemon. Several in series can light an LED faintly.
  • Cells in series add voltages; in parallel they keep the voltage and add capacity. A reversed cell subtracts.

Where this comes from

Sources

  • Series Circuits (opens another website) — The Physics Classroomawaiting owner check

    Supports "the current in a series circuit is everywhere the same", resistances adding (Req = R1 + R2 + R3 + …), the voltage drops summing to the supply voltage, and bulbs appearing dimmer as more resistance is added in series.

  • Parallel Circuits (opens another website) — The Physics Classroomawaiting owner check

    Supports every branch getting the full battery voltage (Vbattery = V1 = V2 = V3 = …), the current outside the branches equalling the sum of the branch currents, and equivalent resistance falling (and total current rising) as more parallel branches are added.

  • Ohm's Law (Delta V-I-R Relationship) (opens another website) — The Physics Classroomawaiting owner check

    Supports the relationship ΔV = I × R and its statement in words, underpinning the fixed-resistor experiment.

  • Circuit Symbols and Circuit Diagrams (opens another website) — The Physics Classroomawaiting owner check

    Supports the use of conventional circuit symbols to draw a schematic diagram, and the symbols for a cell/battery, connecting wire, resistor and open switch used in the bench investigations. (This page does not show ammeter, voltmeter or fuse symbols.)

  • Introduction to circuits - Electricity - KS3 Physics (opens another website) — BBC Bitesizeawaiting owner check

    Supports the battery symbol being made by joining two or more cell symbols, and the rule for connecting meters: "Ammeters are connected in series with components" and "Voltmeters are connected in parallel with components".

  • Incandescent light bulb (opens another website) — Wikipediaawaiting owner check

    Secondary source: "The cold resistance of tungsten-filament lamps is about 1/15 the resistance when operating. For example, a 100-watt, 120-volt lamp has a resistance of 144 ohms when lit, but the cold resistance is much lower (about 9.5 ohms)", and the switch-on inrush.

  • Fuse (electrical) (opens another website) — Wikipediaawaiting owner check

    Secondary source: "If too high of a current flows, the element rises to a higher temperature and either directly melts, or else melts a soldered joint within the fuse, opening the circuit", and the comparison of fuse response times (as fast as 0.002 s) with circuit breakers (typically 0.02–0.05 s).

  • Lemon battery (opens another website) — Wikipediaawaiting owner check

    Secondary source: "a typical voltage is 0.9 V with lemons"; "Currents are more variable, but range up to about 1 mA (the larger the electrode surfaces, the bigger the current)"; and that connecting cells in series increases the voltage available.

End of Investigate

What you just read

  • Plan a fair circuit investigation with independent, dependent and control variables, repeat readings and an uncertainty estimate.
  • Connect ammeters in series and voltmeters across components, and read meters and scales safely and honestly.
  • Predict and test current, voltage and brightness in series and parallel circuits, and explain why homes are wired in parallel.
  • Use a V–I table to decide whether a component is ohmic, and explain why a filament bulb is not.
  • Add appliance currents to predict overloads and explain what fuses, MCBs and short circuits do.

The web

Explore a connection

  • Usesanother area

    Data handling

    A family's monthly electricity use varies; the mean, median and range of a year of bills show what is typical.

  • Usesanother area

    Number system

    Power stations are rated in megawatts and India uses lakhs of crores of units a year: reading such numbers needs place value and the Indian system.

  • Usesanother area

    Four operations

    An electricity bill is units × rate per unit, plus fixed charges, minus subsidies — all four operations in one sheet of paper.

Want to save topics or ask for new ones? Invited families can connect a learning device. Everything here stays free to read without signing in.

Revision 1 · release preview-7e1cbbcc4f · accepted 20/09/2026