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Data handlingGo deeperabout 55 min

Why averages work, and which one to trust

Balance points, proofs, grouped data, combined groups and the art of choosing an average

Prove the mean is a balance point and how it reacts to shifts and scaling. Combine groups correctly, handle grouped data with class intervals, read double bar graphs, and choose between mean, median and mode with outliers, cricket averages and average speeds. Plus a history of statistics in India.

Start at chapter 1

In this part you’ll

  • Explain why deviations from the mean always add to zero, and use sum = mean × count in proofs.
  • Prove how adding a constant or multiplying by a constant changes the mean, median, mode and range.
  • Find a combined (weighted) mean and avoid averaging averages.
  • Group data into class intervals, find the modal class and estimate the mean from midpoints; read double bar graphs.
  • Choose and justify the right average for a situation, including outliers, cricket batting averages and average speed.

You can now calculate every average and predict how it behaves. This layer asks why. Why does sum ÷ count give a fair share? Why must deviations from the mean cancel out? Why is averaging two class averages usually wrong? Why is a cricketer's "average" not the mean of their scores? And when a newspaper says "the average Indian…", which average should it be using?

The arguments here are the kind mathematicians call proofs: reasons that work for every data set, not just the examples we try.

The class marks, salaries and journeys used as examples here are invented; the rainfall figures and Bradman's record are real, and the chapters say where they come from.

Chapter 01

The mean is a balance point

Put a ruler on your finger and place identical coins at the positions 3, 4, 5, 6 and 7 cm. Where must your finger go for the ruler to balance? At 5 cm, the mean. Move the coin at 7 to 12 and the balance point shifts right, to 6 cm, which is the new mean (3 + 4 + 5 + 6 + 12 = 30, and 30 ÷ 5 = 6).

This is not a coincidence. The mean is exactly the point where the "pull" of the values on each side cancels out. To see why, measure each value's deviation: how far it is from the mean, with a sign (+ above, − below).

TableDeviations from the mean for 3, 7, 4, 6, 5 (mean 5)
Value xDeviation x − 5Meaning
3−22 below
7+22 above
4−11 below
6+11 above
50on the mean
Sum0below and above cancel

Worked example

0 / 5 steps shown

Proof: deviations from the mean always add to 0

Show that for any data set, the deviations from the mean add up to zero.

Try it

Chapter 02

Properties of the mean, proved

Investigate showed by experiment that adding a constant shifts the mean and multiplying scales it. Now we can prove it using nothing but sum = mean × count.

Worked example

0 / 5 steps shown

Proof: add k to every value → the mean increases by k

n values have mean M. Each value is increased by k. Show the new mean is M + k.

sum = mean × count
The master key: switch between an average and a total.
Σ(x − mean) = 0
Deviations from the mean always cancel out.
mean(x + k) = mean(x) + k
Shifting every value shifts the mean; the range is unchanged.
mean(k × x) = k × mean(x)
Scaling every value scales the mean; the range is scaled too.
combined mean = total ÷ total count
Never just average the averages when group sizes differ.

Try it

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Try it

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Chapter 03

Combining groups: the weighted mean

Section A of Class 7 has 30 students with a mean mark of 62. Section B has 20 students with a mean of 72. What is the mean of all 50 students?

It is tempting to say (62 + 72) ÷ 2 = 67. That is wrong. Section A has more students, so its average should count for more. Go back to totals:

  • Section A total = 30 × 62 = 1,860.
  • Section B total = 20 × 72 = 1,440.
  • All 50 students: (1,860 + 1,440) ÷ 50 = 3,300 ÷ 50 = 66.

The combined mean, 66, is closer to Section A's 62 because Section A is bigger. This is called a weighted mean: each group's mean is weighted by its size.

Worked example

0 / 4 steps shown

A weighted report card

A school counts the final exam as 60% of a subject grade, the half-yearly as 30% and projects as 10%. Meera scored 80 in the final, 70 in the half-yearly and 95 in projects. What is her grade?

Try it

Worked example

0 / 5 steps shown

The average-speed trap

A family drives 120 km to a wedding at 60 km/h and returns the same 120 km at 40 km/h because of traffic. What is the average speed for the whole trip?

Chapter 04

Grouped data and class intervals

When data has many different values, a frequency table with one row per value becomes long and bumpy. Here is an invented but realistic set of marks (out of 50) for 40 students in a Class 8 test:

8, 22, 47, 18, 13, 49, 40, 39, 22, 30, 37, 48, 30, 27, 32, 33, 39, 31, 36, 21, 17, 43, 17, 47, 27, 21, 22, 39, 29, 28, 39, 45, 38, 28, 30, 19, 7, 33, 20, 24.

Almost every mark appears only once or twice, so a mark-by-mark table tells us little. Instead we group the marks into class intervals of equal width: 0–10, 10–20, 20–30, 30–40, 40–50.

TableTest marks of 40 students grouped into class intervals (lower limit included)
MarksTallyFrequency fMidpoint xf × x
0–10||2510
10–2051575
20–30卌 卌 ||1225300
30–40卌 卌 ||||1435490
40–50卌 ||745315
Total401,190

Worked example

0 / 5 steps shown

Summarising grouped data

Use the grouped table to find the modal class, the class containing the median, and an estimate of the mean. Compare the estimate with the exact mean.

Try it

Using the convention "lower limit included, upper limit excluded", in which class interval does a mark of 40 belong?

Chapter 05

Double bar graphs: comparing side by side

A double bar graph puts two related data sets on the same axes, with a pair of bars for each category and a legend saying which bar is which. It is the natural way to compare two groups, two years or two places.

India has two monsoons. Mumbai, on the west coast, is soaked by the south-west monsoon from June to September. Chennai, on the east coast, gets its heaviest rain from the north-east monsoon in October to December. A double bar graph makes the contrast leap out.

TableAverage monthly rainfall: Mumbai (Santacruz) and Chennai (Nungambakkam), IMD normals 1991–2020, rounded, mm. ▇ ≈ 50 mm
MonthMumbai (M)Chennai (C)Wetter city
JanM 0C 16Chennai
FebM 0C 6Chennai
MarM 0C 2Chennai
AprM 0C 14Chennai
MayM 7C ▇ 43Chennai
JunM ▇▇▇▇▇▇▇▇▇▇▇ 526C ▇ 59Mumbai
JulM ▇▇▇▇▇▇▇▇▇▇▇▇▇▇▇▇▇▇ 920C ▇▇ 102Mumbai
AugM ▇▇▇▇▇▇▇▇▇▇▇ 561C ▇▇▇ 133Mumbai
SepM ▇▇▇▇▇▇▇▇ 384C ▇▇▇ 146Mumbai
OctM ▇▇ 91C ▇▇▇▇▇▇ 300Chennai
NovM 11C ▇▇▇▇▇▇▇ 374Chennai
DecM 2C ▇▇▇▇ 182Chennai

Worked example

0 / 4 steps shown

Reading the double bar graph

Using the table: (a) In how many months is Chennai wetter than Mumbai? (b) Which city has more rain in the year, and by how much? (c) Which city's rainfall is more concentrated in its wettest three months?

Chapter 06

Choosing the right average

Nine people sit in a tea stall. Each earns about ₹25,000 a month. Their mean, median and mode income are all ₹25,000. Then a billionaire walks in who earns ₹100 crore a month.

  • Total income in the room: 9 × 25,000 + 1,00,00,00,000 = ₹1,00,02,25,000.
  • Mean income: ₹1,00,02,25,000 ÷ 10 = ₹10,00,22,500, about ₹10 crore a month each!
  • Median income: the 10 values in order are nine 25,000s and one 100 crore; the middle two (5th and 6th) are both 25,000, so the median is ₹25,000.
  • Mode: ₹25,000.

The mean now describes nobody in the room. Nine people earn far less, and one earns ten times more. This is why reports on incomes, house prices and wealth use the median: it tells you about a typical person, not about how much money is in the room.

TableWhich average to use
AverageBest when…WeaknessExample
MeanData is numerical and fairly symmetric, or the total mattersDragged by outliersMean daily electricity use to size a solar panel
MedianData is skewed or has outliers; you want a typical memberIgnores how big the extremes areTypical income, house price, waiting time
ModeData is categorical, or only actual values make senseMay not exist or may not be uniqueMost popular flavour, shoe size to stock
(Range)Not an average: describes spreadUses only two valuesTemperature swing in a day

Lab

See how one very high salary makes the mean misleading while the median still describes a typical worker.

Monthly pay at a small workshop (₹ thousand), owner included (₹ thousand)

Round 1 / 4★ 0 ptsBest: 0

Challenge 1The owner cuts their own pay. What pay makes the mean ₹40 thousand?

Target: mean = 40. Right now the mean is 72. Add or remove dots below — it checks as you go.

0408012016020024028032036040020 ₹ thousand — click to remove20 ₹ thousand — click to remove30 ₹ thousand — click to remove30 ₹ thousand — click to remove30 ₹ thousand — click to remove40 ₹ thousand — click to remove40 ₹ thousand — click to remove50 ₹ thousand — click to remove60 ₹ thousand — click to remove400 ₹ thousand — click to removemedian 35mean 72

Tap the number line to add a value; tap a dot to remove it. Dashed long line = mean (●), dotted line = median (▲).

The values (10)

  • 20
  • 20
  • 30
  • 30
  • 30
  • 40
  • 40
  • 50
  • 60
  • 400
Mean (share it out equally)72 ₹ thousand

sum ÷ count = 720 ÷ 10 = 72

Median (the middle value)35 ₹ thousand

202030303040405060400

10 values (even), so take the two middle ones: (30 + 40) ÷ 2 = 35.

Mode (most common)30

30 appears 3 times — more than any other value.

Range (spread)380 ₹ thousand

max − min = 400 − 20 = 380

Text version of this activity

A dot plot of 10 monthly pays (₹ thousand): 20, 20, 30, 30, 30, 40, 40, 50, 60 and the owner's 400. Sum 720, so the mean is 72, higher than 9 of the 10 people. Median = (30 + 40) ÷ 2 = 35. Mode 30. Range 400 − 20 = 380.

Challenges:

  1. Mean 40: the total must be 400, so the owner's pay must fall by 320, to 80.
  2. Median 40: the 5th and 6th ordered pays must average 40. Raising one ₹30 thousand worker to 40 works: ordered 20, 20, 30, 30, 40, 40, 40, … so the 5th and 6th are both 40.
  3. Mode 20 only: 20 must appear more than 30 does; move two ₹30 thousand workers to ₹20 thousand (20 appears 4 times, 30 once).
  4. Range 50: change the owner's 400 to 70 (70 − 20 = 50).

The owner's pay controls the mean and range, but has no effect on the median or mode.

Lab

Choose the most suitable average for twelve real situations and say why.

Which average best describes each situation?

12 cards, 3 bins. Tap a card, then tap its bin. You can also drag, or press a bin’s number key.

Text version of this activity

A sorting game with three bins and 12 situations.

  • Mean (the total matters, or data is symmetric): rainfall for a reservoir; class marks close together; daily electricity use to size a solar system; runs per match for a steady batter.
  • Median (outliers or skew): house prices with mansions; village income with one crorepati; clinic waiting times with one 5-hour wait; race times with one fallen runner.
  • Mode (categories or real values only): ice-cream flavour; shoe size to stock; passengers per auto-rickshaw; blood group.

Three questions help: Is the data categorical? (mode) Are there outliers or a long tail? (median) Does the total matter? (mean)

Chapter 07

Cricket averages are special

In cricket, a batter's batting average is not the mean runs per innings. It is

batting average = total runs ÷ number of times out.

Innings in which the batter was not out (marked with an asterisk, like 45*) add their runs to the total but do not add to the count of dismissals. The idea: a not-out innings is unfinished, so it would be unfair to treat it as a completed score. The side effect: batters who are often not out, like tail-enders or finishers, can have a batting average higher than any "fair share" of their innings.

Worked example

0 / 6 steps shown

Three averages for one batter

In 7 innings a batter scored 12, 45*, 0, 78, 30*, 5, 60 (* = not out). Find the batting average, the mean runs per innings and the median innings.

Lab

Compare a batter's mean and median innings, and see how one big century inflates the mean.

A batter's runs in 10 innings (all out) (runs)

Round 1 / 4★ 0 ptsBest: 0

Challenge 1Replace the century (150) with a score that makes the mean 30.

Target: mean = 30. Right now the mean is 40. Add or remove dots below — it checks as you go.

01530456075901051201351500 runs — click to remove5 runs — click to remove10 runs — click to remove15 runs — click to remove25 runs — click to remove30 runs — click to remove40 runs — click to remove50 runs — click to remove75 runs — click to remove150 runs — click to removemedian 27.5mean 40

Tap the number line to add a value; tap a dot to remove it. Dashed long line = mean (●), dotted line = median (▲).

The values (10)

  • 0
  • 5
  • 10
  • 15
  • 25
  • 30
  • 40
  • 50
  • 75
  • 150
Mean (share it out equally)40 runs

sum ÷ count = 400 ÷ 10 = 40

Median (the middle value)27.5 runs

0510152530405075150

10 values (even), so take the two middle ones: (25 + 30) ÷ 2 = 27.5.

Mode (most common)No mode

Every value appears only once. The usual convention: when nothing repeats, we say there is no mode.

Range (spread)150 runs

max − min = 150 − 0 = 150

Text version of this activity

A dot plot of 10 innings: 0, 5, 10, 15, 25, 30, 40, 50, 75, 150. Total 400, mean 40, median (25 + 30) ÷ 2 = 27.5, no mode, range 150.

The one century pulls the mean 12.5 runs above the median. In half of the innings the batter made 25 or fewer.

Challenges:

  1. Mean 30: the total must be 300, so change 150 to 50.
  2. Median 40: the 5th and 6th ordered scores must average 40; e.g. change 25 → 40 and 30 → 40.
  3. Mean 50 with one change: the total must be 500, 100 more; change any innings by +100 within the 0–150 scale, e.g. 0 → 100 or 50 → 150.
  4. Range 100: change 150 to 100.

Try it

Chapter 08

Measuring spread more robustly

The range has the same weakness as the mean: one outlier can wreck it. In the ten values 12, 14, 15, 15, 16, 17, 18, 19, 20, 48, the range is 48 − 12 = 36, but nine of the ten values lie within just 8 of each other.

A sturdier idea, used from Class 9 onwards, is the interquartile range (IQR). Put the data in order and split it into two halves. The median of the lower half is the lower quartile, the median of the upper half is the upper quartile. The IQR is their difference, and it measures the spread of the middle half of the data, ignoring the extremes.

Here the lower half is 12, 14, 15, 15, 16 (median 15) and the upper half is 17, 18, 19, 20, 48 (median 19). IQR = 19 − 15 = 4, a far better description of how spread out most values are.

Chapter 09

A short history of counting people and things

Collecting data is as old as governments. Rulers needed to know how many people, fields and animals they had, to raise taxes and armies and to plan for famine. The word statistics itself comes from state: it began as "facts about the state".

India has a long record. The Arthashastra, a text on statecraft traditionally linked with Kautilya (Chanakya) more than 2,000 years ago, describes officials who kept records of households, land and livestock. Under Akbar, Raja Todar Mal's revenue system measured land and recorded crop yields, and Abul Fazl's Ain-i-Akbari is packed with tables of data about the empire. Modern India has one of the largest statistical systems in the world, and one of its founders, P. C. Mahalanobis, is remembered on 29 June, his birthday, as National Statistics Day.

From clay tablets to the Census of India

  1. c. 300 BCE
    Arthashastra A text on statecraft describes keeping records of population, land and cattle for taxation.
  2. 1590s
    Ain-i-Akbari Abul Fazl's record of Akbar's empire includes detailed revenue and crop data from Todar Mal's land surveys.
  3. 1786
    The bar graph William Playfair, a Scottish engineer, publishes some of the first bar charts; he later popularises the pie chart (1801).
  4. 1858
    Nightingale's diagrams Florence Nightingale uses coloured diagrams of army death data to show that most soldiers died of disease, and wins hospital reform.
  5. 1872
    First census in India The first census across much of British India is completed in 1872, counted area by area over several years rather than everywhere on one date.
  6. 1881
    First synchronous census The first census counting everyone as at the same date; since then India has held a census about every ten years.
  7. 1931
    Indian Statistical Institute P. C. Mahalanobis founds the ISI in Kolkata, which becomes a world centre for statistics and sample surveys.
  8. 1950
    National Sample Survey India begins large nationwide sample surveys of households to measure spending, jobs and living conditions.
  9. 2011
    Census 2011 The 15th census counts about 121 crore people (1,21,08,54,977).
  10. 2026–27
    Census 2027 The census due in 2021 was postponed. India's 16th census is its first digital one: houses are listed between April and September 2026, people are counted in February 2027, and the reference moment is midnight on 1 March 2027.

Chapter 10

Round-up

Lab

Connect the properties of the mean to their effects, and the Deepen examples to their answers.

Match each situation to its effect or value.

9 pairs are hiding in two mixed-up columns. Pick one from each side to join them.

Text version of this activity

Nine pairs:

  • Add 10 to every value → mean rises by 10; range unchanged.
  • Multiply every value by 3 → mean and range both multiplied by 3.
  • Add a new value equal to the mean → mean unchanged.
  • Sum of deviations from the mean → always 0.
  • Mean × number of values → the sum.
  • Remove a value above the mean → mean goes down.
  • 30 students with mean 62 and 20 with mean 72 → combined mean (1,860 + 1,440) ÷ 50 = 66.
  • 120 km at 60 km/h and back at 40 km/h → 240 km in 5 hours = 48 km/h.
  • 6,996 runs and 70 dismissals → batting average ≈ 99.94 (Bradman).

Lab

Rapid practice with totals, missing values, combined means and batting averages.

10 questions on multiplication, division with some word problems mixed in.

Get three in a row and the numbers level up!

Text version of this activity

A sprint of multiplication and division warm-ups, then eight word problems:

  • Mean 15 of 8 numbers → sum 8 × 15 = 120.
  • Mean 12 of 5 numbers → total 60; fifth = 60 − 47 = 13.
  • 630 runs, 14 dismissals → 45.
  • 20 × 140 + 30 × 145 = 2,800 + 4,350 = 7,150; ÷ 50 = 143 cm.
  • Mean 23, add 7 to each → 30.
  • 60 km at 30 km/h (2 h) + 60 km at 60 km/h (1 h) → 120 ÷ 3 = 40 km/h.
  • Midpoints 15 and 25: (4 × 15 + 6 × 25) ÷ 10 = 210 ÷ 10 = 21.
  • Total 500 − 95 = 405; ÷ 9 = 45.

Words from this layer

deviation
How far a value is from the mean, with a sign: positive above, negative below.
Example: 7 − 5 = +2.
balance point
The point where the values' deviations cancel out; the mean.
weighted mean
A mean in which some values or groups count more than others, according to their weights (such as group sizes).
Example: Combined mean of two sections.
class interval
A range of values used as one group in grouped data, such as 20–30.
class width
The difference between the upper and lower limits of a class interval.
Example: 30 − 20 = 10.
lower limit / upper limit
The smallest and largest boundaries of a class interval; usually the lower is included and the upper excluded.
midpoint (class mark)
The middle of a class interval, (lower + upper) ÷ 2, used to estimate the mean of grouped data.
Example: (20 + 30) ÷ 2 = 25.
modal class
The class interval with the highest frequency.
histogram
A bar graph for grouped continuous data, with bars touching because the intervals join up.
double bar graph
A bar graph with pairs of bars for comparing two data sets, with a legend.
legend
The key on a graph that says what each colour or bar style stands for.
batting average
In cricket, total runs divided by the number of times the batter was out.
Example: 6,996 ÷ 70 ≈ 99.94.
quartiles
The values that cut ordered data into four equal parts; the lower and upper quartiles are the medians of the two halves.
interquartile range (IQR)
Upper quartile − lower quartile: the spread of the middle half of the data.
statistics
The science of collecting, organising, summarising and interpreting data; the word comes from "state".

Quick check

Reasoning check

10 questions · answer what you can, then check. Getting one wrong is useful.

  1. Q1The deviations from the mean of a data set are 3, −5, 1, x. What is x?
  2. Q2Class A (10 students) has mean 80; Class B (40 students) has mean 60. The combined mean is…
  3. Q3Going to school at 10 km/h and returning the same distance at 15 km/h, the average speed is…
  4. Q4A batter scores 300 runs in 10 innings, 4 of them not out. Batting average?
  5. Q5In grouped data with intervals 0–5, 5–10, 10–15, where is the value 10?
  6. Q6Estimated mean: 3 values in 0–10 and 7 values in 10–20?
  7. Q7For describing a typical family income in a city, the best average is usually…
  8. Q8Every value is multiplied by 5 and then 2 is added. The range was 6. It becomes…
  9. Q9Which measure of spread ignores the most extreme values?
  10. Q10When is the mean of two group means equal to the overall mean?

Keep this

Cheat sheet

  • Deviations from the mean always add to 0: the mean is the balance point. Proof: Σx − n × mean = S − S = 0.
  • sum = mean × count is the master key for proofs, missing values and combined groups.
  • Add k to all values → mean, median, mode + k, range same. Multiply all by k → all × k (range by the size of k).
  • Combined mean = (n₁ × mean₁ + n₂ × mean₂) ÷ (n₁ + n₂). Never average averages of unequal groups.
  • Average speed = total distance ÷ total time, not the mean of the speeds.
  • Grouped data. Lower limit included, upper excluded. Modal class = highest frequency. Estimated mean uses midpoints.
  • Histogram: bars touch. Double bar graph: paired bars plus a legend.
  • Which average? Categories → mode. Outliers or skew → median. Total matters or symmetric → mean.
  • Batting average = runs ÷ times out (not innings). Bradman: 6,996 ÷ 70 ≈ 99.94.
  • IQR = upper quartile − lower quartile: a spread measure that resists outliers.

Reflect

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Helps you understand

Order of operations

Weighted means like (30 × 62 + 20 × 72) ÷ 50 need the correct order of operations.

Helps you understand

Properties of numbers

The proof that deviations sum to zero uses the distributive property: n × M = M + M + … + M.

Related to

Angles

Pie charts, in the next layer, turn frequencies into angles at the centre of a circle.

Used in

Electricity

Sizing a rooftop solar system uses the mean daily electricity use, because the total energy is what matters.

Where this comes from

Sources

End of Go deeper

What you just read

  • Explain why deviations from the mean always add to zero, and use sum = mean × count in proofs.
  • Prove how adding a constant or multiplying by a constant changes the mean, median, mode and range.
  • Find a combined (weighted) mean and avoid averaging averages.
  • Group data into class intervals, find the modal class and estimate the mean from midpoints; read double bar graphs.
  • Choose and justify the right average for a situation, including outliers, cricket batting averages and average speed.

The web

Explore a connection

  • Builds on

    Number system

    Reading, comparing and rounding numbers comes first when you sort data and round a mean.

  • Builds on

    Four operations

    Finding a mean means adding every value and dividing by how many there are.

  • Uses

    Angles

    In a pie chart each slice's angle shows a share of the data: 360° stands for the whole.

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Revision 1 · release preview-7e1cbbcc4f · accepted 20/09/2026