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GravityGo deeperabout 50 min

The mathematics behind every number in this topic

G, orbits derived from first principles, Newton’s Moon test in full, and the coincidence Einstein could not ignore

Meet Newton’s law with its constant G, derive orbital and escape speed from scratch, redo Newton’s Moon test in full, explore why gravitational and inertial mass are equal, see why g is not uniform on Earth, and look at the mechanics behind ISRO’s orbit-raising missions.

Start at chapter 1

In this part you’ll

  • State and use F = G m1 m2 ÷ r², and show it reduces to weight = mass × g at a world’s surface.
  • Derive orbital speed and escape velocity from force and energy arguments, and explain why their ratio is always √2.
  • Explain Kepler’s third law as a consequence of Newton’s law, and use it to predict an orbital period.
  • Describe the equivalence of gravitational and inertial mass and why it puzzled Newton but inspired Einstein.
  • Explain why g varies slightly across Earth, and how a Hohmann transfer minimises fuel between two orbits.

Understand gave you weight = mass × g and treated g as a fixed number for each world. This layer asks the harder question: where does g itself come from?

The answer is Newton's full law of universal gravitation, with an actual number, G, that lets you calculate the force between any two masses anywhere — a pencil and a planet, two people on a bus, or the Sun and the Earth. From that one equation you can derive g on any world, the exact speed of any orbit, escape velocity, Kepler's laws, and the reason nobody has ever fully explained why gravity and inertia use the same mass.

Chapter 01

Newton’s law, with an actual number

Newton's law of universal gravitation, in full:

F = G × m₁ × m₂ ÷ r²

F is the force in newtons, m₁ and m₂ are the two masses in kilograms, r is the distance between their centres in metres, and G is the universal gravitational constant — the same number everywhere in the universe, for every pair of masses that has ever existed.

G = 0.0000000000667, or 6.674 × 10⁻¹¹ N·m²/kg².

G is almost unimaginably small. That smallness is why gravity between everyday objects is too weak to notice, and why it takes a mass as big as a planet before the force becomes obvious.

Worked example

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The pull between two people, calculated exactly

Two friends, each of mass 50 kg, stand 1 metre apart. Use Newton's law to find the gravitational force between them.

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Worked example

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Checking the law against something familiar: your own weight

Use Newton’s law directly — not weight = mass × g — to calculate the force between the Earth (mass 5.9722 × 10²⁴ kg) and a 40 kg child standing on its surface (radius 6.371 × 10⁶ m). Compare with the Understand-layer answer of 392 N.

Need a different angle?
g = G × M ÷ r²
Surface gravity comes directly from Newton’s law with m₁ = M (the world) and r = its radius.
G × M_Earth ÷ R_Earth² ≈ 9.82 N/kg
Using Earth’s real mass and radius, matching the measured value to three figures.
G × M_Mars ÷ R_Mars² ≈ 3.73 N/kg
Every g value in this topic comes from exactly this calculation.
G
6.674 × 10⁻¹¹N·m²/kg². Measured by Cavendish, 1798, using a torsion balance.
G × M_Earth
3.986 × 10¹⁴This combination, "standard gravitational parameter", appears in every Earth-orbit formula.
Two 50 kg friends, 1 m apart
≈ 1.67 × 10⁻⁷ NReal, calculable, and about 6 million times smaller than the weight of an apple.
Force, Sun on Earth
≈ 3.54 × 10²² NEnough to bend a planet’s path into a year-long orbit.
Equivalence precision, 2017
better than 1 in 10¹⁴The MICROSCOPE satellite’s test of gravitational vs inertial mass.

Try it

Chapter 02

Deriving orbital speed from first principles

Understand gave you the orbital speed at Earth’s surface as a fact: about 7.91 km/s. Here is where that number actually comes from.

For an object moving in a circle, staying on the circle requires a centripetal force pointing towards the centre, equal to m × v² ÷ r. For an orbiting object, gravity is that force. Setting the two equal:

G × M × m ÷ r² = m × v² ÷ r

Notice m — the orbiting object's own mass — appears on both sides and cancels immediately. This is the same "mass cancels" idea from Understand, showing up a third time, in orbits. Rearranging what is left:

v = √(G × M ÷ r)

This is the exact formula behind every orbital speed in this topic.

Worked example

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Using the orbit formula to get 7.91 km/s exactly

Use v = √(G M ÷ r) to find the circular orbital speed just above Earth’s surface (r ≈ 6.371 × 10⁶ m, using G M = 3.986 × 10¹⁴, the standard value for Earth).

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Worked example

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Deriving escape velocity from energy, not force

Escape velocity comes from a different argument: energy, not force. An object escapes if its kinetic energy at launch is enough to climb out of the planet’s gravity well entirely, ending with (just barely) zero speed infinitely far away. Setting kinetic energy equal to the gravitational potential energy it must overcome: ½ m v² = G M m ÷ r. Solve for v.

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Worked example

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The same two formulas, on a much bigger world

Jupiter's cloud tops are 7.1492 × 10⁷ m from its centre, and Jupiter's mass is 1.8982 × 10²⁷ kg. Find the orbital and escape speeds just above the cloud tops.

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Worked example

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Newton’s cannon, made exact

Understand argued informally that "fall 5 m while going 8 km sideways" gives an orbit. Make it exact: a circular orbit needs the sideways fall in one second, ½ g t², to equal the amount the round Earth’s surface drops away, v² t² ÷ (2R), in that same second. Show this leads to v = √(g R), and that it matches v = √(G M ÷ R).

Need a different angle?
TableKepler’s third law tested: period squared grows with distance cubed
OrbitRadius (Earth radii or AU)Predicted period (from r^1.5 scaling)Actual period
ISS≈ 1.06 Earth radii(reference orbit)≈ 92.4 min
Geostationary≈ 6.62 Earth radii(1.06 ÷ 6.62)⁻¹·⁵ × 92.4 min ≈ 23.93 h23 h 56 min, by design
Mars around the Sun1.524 AU (Earth = 1 AU)1.524^1.5 × 365.25 days ≈ 687.2 days≈ 687 days

Try it

years

Chapter 03

Ellipses: why a spacecraft speeds up and slows down

Every orbit lab so far has shown circles alongside stretched ellipses without dwelling on one detail: on an ellipse, speed is not constant. A spacecraft on an elliptical path moves fastest at its closest point to Earth (perigee) and slowest at its farthest point (apogee).

This is Kepler's second law, found (like his third) purely from observation, decades before Newton: a line from the planet to the Sun sweeps out equal areas in equal times. Close to the Sun, that line is short, so the planet must move quickly to sweep the same area; far away, the line is long, so it can move slowly and still sweep the same area.

Worked example

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How much faster at perigee than at apogee?

A spacecraft is in an elliptical orbit with perigee 300 km above Earth’s surface and apogee 200,000 km above the surface. Using the vis-viva equation v = √(G M × (2 ÷ r − 1 ÷ a)), where a is the semi-major axis, find the speed at each point and their ratio.

Need a different angle?

Predict first

A comet follows a very stretched ellipse around the Sun, spending most of its time far out in the outer Solar System and swinging in close to the Sun only briefly every few decades. Where is it moving fastest?

Chapter 04

Newton’s Moon test, in full

Investigate showed you the two numbers side by side. Here is the reasoning behind each one, precisely.

The predicted acceleration comes from taking the surface value g = 9.8 N/kg and scaling it down by the inverse square of how much further away the Moon is than the Earth’s surface: a distance ratio of 384,400 ÷ 6,371 ≈ 60.3.

predicted a = 9.8 ÷ 60.3² ≈ 9.8 ÷ 3,640 ≈ 0.00269 m/s²

The observed acceleration treats the Moon as a satellite on a circular path and uses pure kinematics: for circular motion, centripetal acceleration = v² ÷ r. The Moon’s orbital speed, from its known circumference and 27.32-day period, is about 1.02 km/s, and its distance is 384,400 km:

observed a = v² ÷ r = (1,023)² ÷ 384,400,000 ≈ 0.00272 m/s²

The two agree to within about 1.2 % — well inside the accuracy Newton could have expected from 17th-century measurements of the Earth’s size and the Moon’s distance.

Predict first

Suppose you wanted to run the same style of test on Mars’s moon Phobos, which orbits much closer to Mars than our Moon orbits Earth. What would you need to know to predict Phobos’s acceleration using the inverse-square method?

Chapter 05

The coincidence Newton could not explain

Go back to Understand’s Chapter 4: mass cancels in free fall because gravitational force and inertia both scale with the same mass. Stated as an equation:

gravitational mass (in F = G M m ÷ r²) = inertial mass (in F = m a)

These come from two entirely different definitions. Gravitational mass measures how strongly a world pulls on an object. Inertial mass measures how stubbornly the object resists being pushed, by anything — a rocket engine, a cricket bat, a car crash — with no gravity involved at all. There is no obvious reason these should be the same number.

Every experiment ever performed says they are equal, to a precision better than one part in 10¹⁴ in the most careful modern tests using satellites built specifically to check it. Newton knew about the equality and used it, but had no explanation for why it should be true. It sat, unexplained, for over two centuries.

From a puzzling coincidence to a foundation of physics

  1. 1687
    Newton, Principia Uses the equality of gravitational and inertial mass freely, and tests it with pendulums of different materials, but offers no explanation for why it holds.
  2. 1889-1908
    Eötvös A Hungarian physicist tests the equality with a sensitive torsion balance, to about one part in a billion, finding no difference at all.
  3. 1907
    Einstein’s "happiest thought" Einstein realises that someone falling freely feels no gravity at all — the seed of the equivalence principle.
  4. 1915
    General relativity Einstein builds a full theory of gravity from the idea that gravitational and inertial mass are equal for a deep reason: gravity is not really a force, but the curving of spacetime itself.
  5. 2017
    MICROSCOPE satellite A dedicated French space mission tests the equivalence to about one part in 10¹⁴ — the most precise test yet, and still no measurable difference.

Lab

Sort six statements about the mathematics of gravity into true and false.

Is this statement about the deeper theory true or false?

6 cards, 2 bins. Tap a card, then tap its bin. You can also drag, or press a bin’s number key.

Text version of this activity

True: Newton’s law applies to any two masses; escape velocity is always √2 times orbital speed; the Moon test combined two independent methods.

False: g = 9.8 is a separate rule (it is Newton’s law applied at a surface); Kepler used Newton’s equations (the reverse is true — Newton later explained Kepler’s patterns); gravitational and inertial mass have ever been shown to differ.

Chapter 06

Why g is not quite the same everywhere on Earth

Newton’s law says g = G M ÷ r², which depends only on distance from the centre — so in principle g should be identical at every point on a perfectly spherical, non-spinning Earth. Real measurements show small but very real differences, for two reasons.

The Earth is not a perfect sphere. Spinning for billions of years has flattened it very slightly, so the equator bulges outward: about 21 km further from the centre than the poles. Since the equator is further from the centre, gravity there is very slightly weaker.

The Earth is spinning. Standing at the equator, you are travelling in a circle nearly 1,670 km/h fast, which requires a small centripetal force pointing inward — supplied by gravity, leaving slightly less "spare" force to press you onto a scale. At the poles, you are on the spin axis and feel none of this effect.

Both effects push the same way: weaker gravity at the equator, stronger at the poles — about 9.78 N/kg against 9.83 N/kg, a difference of roughly half a percent.

TableHow g changes with height, ignoring air: all differences are tiny compared with the 9.8 baseline
LocationApproximate gCompared with sea level
Sea level (mid-latitude average)9.80 m/s²reference
Equator9.78 m/s²about 0.2 % weaker
Poles9.83 m/s²about 0.3 % stronger
Summit of Mount Everest (8,849 m)9.79 m/s²about 0.28 % weaker
Cruising airliner altitude (11,000 m)9.79 m/s²about 0.28 % weaker
International Space Station (400 km)8.69 m/s²about 11.3 % weaker

Worked example

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Comparing g at the ISS with g on the ground, precisely

Using g = G M ÷ r², compare gravity at the ISS’s orbital radius (6,371 + 400 = 6,771 km) with gravity at Earth’s surface (6,371 km), and express the ISS value as a percentage of the surface value.

Need a different angle?

Try it

N

Chapter 07

ISRO’s manoeuvres, with the mechanics behind them

Investigate showed what ISRO’s missions did — raise an orbit gradually, then transfer, then insert. Here is a little more of why it works, using the tools from this layer.

Each perigee burn adds speed at a single point of the orbit. Extra speed at any point of an orbit increases the total energy of that orbit, and more orbital energy means the object can coast further out before gravity pulls it back — raising the apogee, exactly as predicted in Investigate. Because the burn happens at perigee, and an orbit’s perigee is fixed by where you were and how fast you were going at that exact point, later burns keep returning to nearly the same perigee to push the apogee out again.

Try it

A spacecraft is on a Hohmann transfer ellipse from Earth’s orbit toward Mars’s. At which point of that ellipse should it fire its engine to settle into a circular orbit around Mars?

Used in

Four operations

Comparing orbital energies and transfer times uses the same arithmetic tools as any other physics calculation — multiplication, ratios and powers.

Chapter 08

Tides: gravity that changes across an object

Gravity pulling on a whole ocean, rather than a single point, produces an effect Understand did not need: a differential pull, stronger on the near side of the Earth than on the far side, because the near side is closer to the Moon.

Because gravity follows an inverse-square law, this difference can be estimated by comparing the pull at the near side (384,400 − 6,371 km from the Moon) with the pull at the far side (384,400 + 6,371 km away). The two are close enough that the difference is small — but not zero, and definitely not nothing.

Worked example

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How much stronger is the pull on the near side?

Using the Moon’s pull ∝ 1 ÷ distance², compare the pull at the Earth’s near side (384,400 − 6,371 = 378,029 km from the Moon) with the pull at the far side (384,400 + 6,371 = 390,771 km), as a percentage difference from the pull at the centre.

Need a different angle?

Helps you understand

Tides

The differential pull across the Earth’s diameter, computed here from the inverse-square law, is the direct cause of the twice-daily tidal bulge explained fully in the tides topic.

Lab

See how a single speed increase at one point of an orbit stretches the far point outward, the same idea behind a Hohmann transfer.

EarthGoes right round — a circular orbit Earth 221 px across · mountain drawn far too tall

Goes right round — a circular orbit

The ball falls exactly as fast as the ground curves away beneath it, so it never gets any closer. It is still falling; it just keeps missing.

Highest point: 74 km up. One lap takes 85 minutes.

The two magic numbers

7.9 km/s — fast enough that the ground curves away underneath you as fast as you fall. That is an orbit: falling for ever and always missing.
11.2 km/s — fast enough to leave for good.

The cannon sits 35 km up, above the thick air, and we pretend there is no air at all. A real cannonball would burn up.

Text version of this activity

Starting from the 7.9 km/s circular orbit, increasing the speed at the same point stretches the orbit into a longer and longer ellipse — 9.5 km/s reaches roughly to the Moon’s distance, 10.5 km/s further still — while the point of the burn itself stays fixed as the orbit’s near point. This is the geometric heart of every orbit-raising manoeuvre in this lesson, from a single perigee burn to a full Hohmann transfer to Mars.

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Chapter 09

Putting the mathematics together

Lab

Match six formulas from this lesson to what each one calculates.

Match each formula to what it calculates.

6 pairs are hiding in two mixed-up columns. Pick one from each side to join them.

Text version of this activity

F = G m1 m2 ÷ r² gives the force between any two masses; g = G M ÷ r² gives a world’s surface gravity; v = √(G M ÷ r) gives circular orbital speed; v = √(2 G M ÷ r) gives escape velocity; T² ∝ r³ is Kepler’s third law; and a = v² ÷ r gives centripetal acceleration on any circular path.

Deeper vocabulary

G
The universal gravitational constant, 6.674 × 10⁻¹¹ N·m²/kg², fixing the strength of gravity everywhere.
Example: F = G m1 m2 / r² uses it directly.
Centripetal acceleration
The acceleration needed to keep an object moving on a circular path, always pointing towards the centre.
Example: For an orbit, gravity supplies it.
Barycentre
The common centre of mass that two orbiting bodies actually circle around.
Example: The Earth–Moon barycentre sits inside the Earth, off-centre.
Hohmann transfer
The lowest-fuel route between two circular orbits: one burn onto a connecting ellipse, one burn to circularise.
Example: Used by Mangalyaan to reach Mars.
Equivalence principle
The observation, later built into general relativity, that gravitational mass and inertial mass are always equal.
Example: Tested to better than one part in 10¹⁴.
Gravimeter
A precise instrument that detects tiny local changes in g, used to study what lies underground.
Example: Can find dense ore or hidden cavities.
Perigee / apogee
The closest and farthest points of an orbit around the Earth.
Example: Speed is highest at perigee, lowest at apogee.
Perihelion / aphelion
The closest and farthest points of an orbit around the Sun — the same idea as perigee/apogee, for a different centre.
Example: A comet moves fastest at perihelion.
Vis-viva equation
The formula v = √(G M (2/r − 1/a)) giving speed anywhere on an elliptical orbit, not just at perigee or apogee.
Example: Used to compare speed at two points of the same ellipse.
Torsion balance
A sensitive instrument that measures a tiny twisting force, used by Cavendish to weigh the Earth and by later scientists to test the equivalence principle.
Example: A beam on a fine wire, twisted by a very small force.

Quick check

Go deeper: check your reasoning

9 questions · answer what you can, then check. Getting one wrong is useful.

  1. Q1Which formula is Newton’s law of universal gravitation?
  2. Q2In deriving orbital speed from G M m / r² = m v² / r, why does the orbiting object’s own mass not appear in the final formula?
  3. Q3Why is escape velocity always exactly √2 times the circular orbital speed, for any planet?
  4. Q4What did Kepler contribute, and what did Newton add?
  5. Q5What is remarkable about gravitational mass and inertial mass?
  6. Q6Why is g slightly weaker at the equator than at the poles?
  7. Q7What makes a Hohmann transfer fuel-efficient?
  8. Q8A spacecraft on an elliptical orbit is 30 times closer to Earth at perigee than at apogee. Roughly how many times faster is it moving at perigee?
  9. Q9What was special about Galileo’s "tied cannonball" argument?

Keep this

Cheat sheet: the equations behind the numbers

  • F = G m1 m2 ÷ r². The full law. G = 6.674 × 10⁻¹¹ N·m²/kg², measured by Cavendish in 1798.
  • g = G M ÷ r² is this same law at a world’s surface. It is not a separate rule from F = G m1 m2 ÷ r².
  • Orbital speed: v = √(G M ÷ r). Derived by setting gravity equal to the centripetal force needed for a circle; the orbiting mass cancels.
  • Escape velocity: v = √(2 G M ÷ r) = √2 × orbital speed, always, for any world — derived from energy, not force.
  • Kepler’s third law, T² ∝ r³, was found from observation decades before Newton, and falls straight out of v = √(GM/r) combined with T = 2πr/v.
  • Newton’s Moon test: predicted 0.00269 m/s² (inverse square from surface g) against observed 0.00272 m/s² (pure orbital kinematics) — about 1.2 % apart.
  • Gravitational mass = inertial mass, to better than one part in 10¹⁴ in the best modern tests — an unexplained fact until Einstein used it as the seed of general relativity.
  • g is not perfectly uniform on Earth: about 9.78 N/kg at the equator, 9.83 N/kg at the poles, because of the equatorial bulge and the Earth’s spin.
  • A Hohmann transfer — one burn onto a connecting ellipse, one burn to circularise — is the minimum-fuel route between two orbits, and the strategy behind ISRO’s Mars and Moon missions.
  • Kepler’s second law: on an ellipse, speed and distance from the centre are in inverse proportion — about 31 times faster at Mangalyaan-style perigee than at its apogee.
  • Galileo’s tied-cannonball argument shows, by pure logic and no experiment, that weight cannot make one object fall faster than another.
  • Tides come from a difference, not a total pull: the Moon’s pull on Earth’s near side is only about 6.6 % stronger than on the far side — small, but enough to raise two ocean bulges at once.

Reflect

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Where this comes from

Sources

  • Gravity and Newton’s law of universal gravitation (opens another website) — HyperPhysics, Georgia State Universityawaiting check

    Supports F = G m₁ m₂ ÷ r², the value of G, the inverse-square fall-off with distance, g = G M ÷ r² at a surface, and circular-orbit and escape-speed relations.

  • Newton’s Law of Universal Gravitation (opens another website) — The Physics Classroomawaiting check

    Supports the apple-and-Moon reasoning, the inverse-square test against the Moon’s acceleration of about 0.0027 m/s², and the statement that gravity acts between every pair of masses.

  • Planetary Fact Sheet (opens another website) — NASA Space Science Data Coordinated Archiveawaiting check

    Supports the masses, radii and surface gravity figures used throughout: Earth 9.8, Moon 1.62, Mars 3.72, Jupiter 24.79, Sun 274 and Pluto 0.62 m/s², plus the Moon’s orbital distance of 384,400 km and speed of about 1.02 km/s.

  • Gravity (opens another website) — Encyclopaedia Britannicaawaiting check

    Supports the history from Galileo and Newton to Einstein, general relativity as curved spacetime (1915), the bending of starlight and the equivalence of gravitational and inertial mass.

  • Mars Orbiter Mission (Mangalyaan) (opens another website) — Wikipediaawaiting check

    Supports the six Earth-orbit-raising burns after the 5 November 2013 launch, trans-Mars injection on 1 December 2013 and Mars orbit insertion on 24 September 2014, and why a small rocket could still reach Mars.

  • Chandrayaan-3 mission (opens another website) — Indian Space Research Organisation (ISRO)awaiting check

    Supports the Chandrayaan-3 launch on 14 July 2023, the Vikram lander’s soft landing near the lunar south pole on 23 August 2023, and the powered-descent problem of shedding about 1.68 km/s with no atmosphere to help.

End of Go deeper

What you just read

  • State and use F = G m1 m2 ÷ r², and show it reduces to weight = mass × g at a world’s surface.
  • Derive orbital speed and escape velocity from force and energy arguments, and explain why their ratio is always √2.
  • Explain Kepler’s third law as a consequence of Newton’s law, and use it to predict an orbital period.
  • Describe the equivalence of gravitational and inertial mass and why it puzzled Newton but inspired Einstein.
  • Explain why g varies slightly across Earth, and how a Hohmann transfer minimises fuel between two orbits.

The web

Explore a connection

  • Helps you understandanother area

    Phases of the Moon

    Gravity is what keeps the Moon in the orbit that produces the monthly cycle of phases.

  • Helps you understandanother area

    Tides

    Tides are gravity made visible: the Moon pulls the near ocean harder than the far ocean.

  • Helps you understandanother area

    Eclipses

    Eclipses happen only because the Sun, Earth and Moon move on fixed gravitational paths we can predict.

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Revision 1 · release preview-7e1cbbcc4f · accepted 20/09/2026