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Order of operationsInvestigateabout 40 min

Brackets under the microscope

Predict, test and explain: moving brackets, missing signs, calculators and targets

Experiment with the order of operations: count how many values brackets can make, find when brackets change nothing, test always/sometimes/never statements, fill in missing signs, compare calculators and hit targets.

Start at chapter 1

In this part you’ll

  • Find all the values an expression can take when brackets are moved, and explain why four numbers have five bracketings.
  • Decide when brackets change a value, using associativity and the order of operations.
  • Test conjectures about removing brackets after − and ÷, and use counterexamples.
  • Predict what basic and scientific calculators show for a key sequence.
  • Solve missing-sign and target puzzles by reasoning and working backwards.

So far you have followed the order of operations. In this layer you will experiment with it. What happens if you move a bracket? How many different answers can the same four numbers make? When do brackets change nothing at all? Is a rule you notice always true, or only sometimes?

That is how mathematicians work: predict, try, compare, and test. You will make guesses (called conjectures), try to break them with a single example that does not fit (a counterexample), and keep only the ideas that survive.

Need a different angle?

Chapter 01

How many answers can brackets make?

Predict first

Take 2 + 3 × 4 − 1 (value 13 with no brackets). You may add brackets anywhere, as many as you like, but you must keep the numbers and signs in the same order. How many different values can you make?

TableAll five ways to bracket 2 + 3 × 4 − 1
Fully bracketedShortest way to write itValue
((2 + 3) × 4) − 1(2 + 3) × 4 − 119
(2 + (3 × 4)) − 12 + 3 × 4 − 1 (no brackets needed)13
(2 + 3) × (4 − 1)(2 + 3) × (4 − 1)15
2 + ((3 × 4) − 1)2 + (3 × 4 − 1)13
2 + (3 × (4 − 1))2 + 3 × (4 − 1)11

Why exactly five? Every fully bracketed expression has a last operation, the one done at the very end. Here there are three signs, so there are three choices for the last one:

  • Last is +: the left side is just 2, and the right side is 3 × 4 − 1, which can be bracketed in 2 ways.
  • Last is ×: left is 2 + 3 (1 way), right is 4 − 1 (1 way): 1 × 1 = 1 way.
  • Last is : left is 2 + 3 × 4 (2 ways), right is 1: 2 ways.

Total: 2 + 1 + 2 = 5. With five numbers the same thinking gives 14 ways, with six numbers 42 ways, then 132, 429… These are called the Catalan numbers, and they turn up all over mathematics (you will meet them again in the Extend layer).

Need a different angle?

Lab

Step through the same numbers with brackets in different places and see how the value changes.

  1. Brackets first. Innermost first: ( ) before [ ].
  2. × and ÷ are equal partners: do them left to right.
  3. + and − are equal partners: do them left to right.

BODMAS or DMAS is just a memory aid. D doesn’t beat M, and A doesn’t beat S. They take turns from left to right.

Expression 1 of 10: tap the operation to do next, or tap an opening bracket.

23)41
Text version of this activity

Ten expressions built from the same numbers with brackets moved around.

From 2, 3, 4, 1 with +, ×, −:

  • (2 + 3) × 4 − 1 = 5 × 4 − 1 = 20 − 1 = 19
  • 2 + 3 × 4 − 1 = 2 + 12 − 1 = 14 − 1 = 13
  • (2 + 3) × (4 − 1) = 5 × (4 − 1) = 5 × 3 = 15
  • 2 + (3 × 4 − 1) = 2 + (12 − 1) = 2 + 11 = 13
  • 2 + 3 × (4 − 1) = 2 + 3 × 3 = 2 + 9 = 11

From 3, 4, 5, 2: (3 + 4) × 5 − 2 = 7 × 5 − 2 = 35 − 2 = 33, 3 + 4 × (5 − 2) = 3 + 4 × 3 = 3 + 12 = 15

From 2, 3, 4, 5 with ×, +, ×: 2 × (3 + 4 × 5) = 2 × (3 + 20) = 2 × 23 = 46, (2 × 3 + 4) × 5 = (6 + 4) × 5 = 10 × 5 = 50, 2 × (3 + 4) × 5 = 2 × 7 × 5 = 14 × 5 = 70

Need a different angle?

Lab

Match each way of bracketing 2 × 3 + 4 × 5 with its value, and notice which bracketings change nothing.

Connect each bracketing of 2 × 3 + 4 × 5 to its value.

5 pairs are hiding in two mixed-up columns. Pick one from each side to join them.

Text version of this activity

A connect-the-pairs game about the numbers 2, 3, 4, 5 with ×, + and ×.

  • 2 × 3 + 4 × 5 = 6 + 4 × 5 = 6 + 20 = 26
  • 2 × (3 + 4 × 5) = 2 × (3 + 20) = 2 × 23 = 46
  • (2 × 3 + 4) × 5 = (6 + 4) × 5 = 10 × 5 = 50
  • 2 × (3 + 4) × 5 = 2 × 7 × 5 = 14 × 5 = 70
  • (2 × 3) + (4 × 5) = 26: these brackets only surround what would be done first anyway, so they change nothing.

The five bracketings give four different values: 26, 46, 50 and 70.

Try it

Chapter 02

When brackets change nothing

Brackets do not always change the value. Test these:

  • (2 + 3) + 4 = 9 and 2 + (3 + 4) = 9.
  • (2 × 3) × 4 = 24 and 2 × (3 × 4) = 24.
  • 2 + (3 × 4) = 14, the same as 2 + 3 × 4.

In the first two, the expression uses only + or only ×. Adding and multiplying are associative: how you group them does not matter. In the third, the brackets just surround a part that would have been done first anyway.

Now test subtraction and division:

  • (20 − 8) − 2 = 12 − 2 = 10, but 20 − (8 − 2) = 20 − 6 = 14.
  • (48 ÷ 4) ÷ 2 = 12 ÷ 2 = 6, but 48 ÷ (4 ÷ 2) = 48 ÷ 2 = 24.

Subtraction and division are not associative. That is precisely why the order of operations needs the left-to-right rule for them.

TableDoes grouping matter? A test table
OperationTest 1Test 2Always the same?
+(5 + 7) + 9 = 21; 5 + (7 + 9) = 21(100 + 1) + 0 = 101; 100 + (1 + 0) = 101Yes: addition is associative
×(5 × 7) × 2 = 70; 5 × (7 × 2) = 70(9 × 1) × 0 = 0; 9 × (1 × 0) = 0Yes: multiplication is associative
(20 − 8) − 2 = 10; 20 − (8 − 2) = 14(9 − 5) − 0 = 4; 9 − (5 − 0) = 4No: test 1 is a counterexample
÷(48 ÷ 4) ÷ 2 = 6; 48 ÷ (4 ÷ 2) = 24(8 ÷ 4) ÷ 1 = 2; 8 ÷ (4 ÷ 1) = 2No: test 1 is a counterexample

Lab

Decide whether adding brackets to an expression changes its value, and spot which kinds of brackets are "free".

Do the brackets change the value? Sort each pair.

12 cards, 2 bins. Tap a card, then tap its bin. You can also drag, or press a bin’s number key.

Text version of this activity

A sorting game with 12 pairs of expressions and two bins: same value or different value.

Same: (4 + 5) + 6 and 4 + (5 + 6) (15); (4 × 5) × 6 and 4 × (5 × 6) (120); 7 + (3 × 2) and 7 + 3 × 2 (13); (18 ÷ 3) × 2 and 18 ÷ 3 × 2 (12); (12 − 5) + 3 and 12 − 5 + 3 (10); (6 × 2) + (8 ÷ 4) and 6 × 2 + 8 ÷ 4 (14).

Different: (30 − 10) − 5 = 15 vs 30 − (10 − 5) = 25; (64 ÷ 8) ÷ 2 = 4 vs 64 ÷ (8 ÷ 2) = 16; (7 + 3) × 2 = 20 vs 13; 18 ÷ (3 × 2) = 3 vs 12; 12 − (5 + 3) = 4 vs 10; (9 − 9) × 5 = 0 vs 9 − 45 = −36.

Brackets change nothing when they only group what the rule would do first anyway, or when only + or only × is involved.

Need a different angle?

Try it

In which expression can the brackets be removed without changing the value?

Chapter 03

Opening a bracket after − or ÷

Here is a real investigation. Compare 20 − (8 + 2) with 20 − 8 + 2.

  • 20 − (8 + 2) = 20 − 10 = 10
  • 20 − 8 + 2 = 12 + 2 = 14

They differ. Now try 20 − 8 − 2 = 12 − 2 = 10. That matches!

Conjecture: when you remove a bracket that has a − in front of it, the signs inside flip: + becomes − and − becomes +.

  • 20 − (8 + 2) = 20 − 8 − 2 ✓ (both 10)
  • 20 − (8 − 2) = 20 − 8 + 2? Left: 20 − 6 = 14. Right: 12 + 2 = 14 ✓

It makes sense: taking away (8 − 2) means taking away 8 but then giving back the 2, because you took away 2 too many.

Predict first

By the same thinking, which of these equals 48 ÷ (4 × 2)?

TableTesting the sign-flip conjecture
With bracketsBrackets removed, signs flippedBoth values
20 − (8 + 2)20 − 8 − 210 and 10
20 − (8 − 2)20 − 8 + 214 and 14
100 − (30 − 10 + 5)100 − 30 + 10 − 575 and 75
48 ÷ (4 × 2)48 ÷ 4 ÷ 26 and 6
48 ÷ (4 ÷ 2)48 ÷ 4 × 224 and 24
50 + (8 − 3)50 + 8 − 355 and 55

Try it

Chapter 04

Always, sometimes or never?

Mathematicians love statements that are always true. But many statements are only sometimes true, and some are never true. Deciding which, and backing it up, is a key skill.

  • To show sometimes, give one example where it works and one where it fails.
  • To show never or always, you need a reason that covers every possible number, not just a few tests.

Try the sort game below. For each statement, test it with a few numbers (include 0 and 1) before you decide.

Lab

Test algebra-style statements about brackets and order with real numbers and decide if each is always, sometimes or never true.

Is each statement always, sometimes or never true for whole numbers? Test with a few numbers first.

12 cards, 3 bins. Tap a card, then tap its bin. You can also drag, or press a bin’s number key.

Text version of this activity

A sorting game with 12 statements and three bins.

Always true: (a + b) + c = a + (b + c); a − (b + c) = a − b − c; a ÷ (b × c) = a ÷ b ÷ c; a × (b + c) = a × b + a × c; a + 1 × b = a + b.

Sometimes true: a + b × c = (a + b) × c (only if a = 0 or c = 1); a × b + c = a × (b + c) (only if a = 1 or c = 0); a − (b − c) = a − b − c (only if c = 0); (a + b) × c bigger than a + b × c (when a > 0 and c > 1); a + b × c = (a + b) × c + 1 (for some numbers only); a − a × 0 = 0 (only when a = 0, since a − a × 0 = a).

Never true: (a + 1) × 0 = a + 1 × 0 for counting numbers a (0 on the left, a on the right).

Need a different angle?

Worked example

0 / 6 steps shown

Proving a "sometimes" statement

When is a + b × c equal to (a + b) × c? Find all the cases.

Chapter 05

Fill in the missing signs

Here is a different kind of puzzle. The numbers are fixed, but the signs are hidden: 6 ▢ 3 ▢ 2. Each box can be +, −, × or ÷. How many different values can you get?

There are 4 × 4 = 16 ways to fill the boxes. Before you look at the table, predict: which filling gives the biggest value? Which gives 0? Are any two fillings equal?

TableAll 16 ways to fill 6 ▢ 3 ▢ 2 (using the order of operations)
ExpressionAfter the first stepValue
6 + 3 + 29 + 211
6 + 3 − 29 − 27
6 + 3 × 26 + 612
6 + 3 ÷ 26 + 3/215/2 (not whole)
6 − 3 + 23 + 25
6 − 3 − 23 − 21
6 − 3 × 26 − 60
6 − 3 ÷ 26 − 3/29/2 (not whole)
6 × 3 + 218 + 220
6 × 3 − 218 − 216
6 × 3 × 218 × 236
6 × 3 ÷ 218 ÷ 29
6 ÷ 3 + 22 + 24
6 ÷ 3 − 22 − 20
6 ÷ 3 × 22 × 24
6 ÷ 3 ÷ 22 ÷ 21

Predict first

Fill the boxes in 8 ▢ 4 ▢ 2 to make 16. Which works?

Lab

Work through expressions made by filling in missing signs, and check which ones hit the target you predicted.

  1. Brackets first. Innermost first: ( ) before [ ].
  2. × and ÷ are equal partners: do them left to right.
  3. + and − are equal partners: do them left to right.

BODMAS or DMAS is just a memory aid. D doesn’t beat M, and A doesn’t beat S. They take turns from left to right.

Expression 1 of 9: tap the operation to do next.

632
Text version of this activity

Nine expressions, each one a possible answer to a missing-signs puzzle. Step through each and compare the value with what you predicted.

  • 6 + 3 × 2 = 6 + 6 = 12
  • 6 × 3 − 2 = 18 − 2 = 16
  • 6 − 3 × 2 + 9 = 6 − 6 + 9 = 0 + 9 = 9
  • 8 × 4 ÷ 2 = 32 ÷ 2 = 16
  • 8 + 4 × 2 = 8 + 8 = 16
  • 12 ÷ 4 + 2 × 3 = 3 + 2 × 3 = 3 + 6 = 9
  • 12 − 4 ÷ 2 × 3 = 12 − 2 × 3 = 12 − 6 = 6
  • 9 × 2 − 12 ÷ 3 = 18 − 12 ÷ 3 = 18 − 4 = 14
  • 5 + 10 ÷ 5 × 3 − 1 = 5 + 2 × 3 − 1 = 5 + 6 − 1 = 11 − 1 = 10

Two different fillings of 8 ▢ 4 ▢ 2 both make 16.

Need a different angle?

Try it

Which filling of 10 ▢ 5 ▢ 5 gives 3?

Chapter 06

Biggest and smallest

Take the digits 1, 2, 3, 4. Use each once, with any of + and ×, and any brackets. What is the biggest value?

You might guess 1 × 2 × 3 × 4 = 24. But try (1 + 2) × 3 × 4 = 36. Adding the 1 to something first is better than multiplying by 1, because multiplying by 1 changes nothing.

This leads to a useful observation: for numbers bigger than 2, multiplying beats adding; but 1s should be added, not multiplied. (2 and 2 are a tie: 2 + 2 = 2 × 2 = 4.)

TableWhen does multiplying beat adding?
Paira + ba × bWinner
1 and 565add
1 and 121add
2 and 244tie
2 and 356multiply
3 and 369multiply
5 and 71235multiply
0 and 990add

Predict first

Using 2, 3, 4, 5 once each with + and × and any brackets, what is the smallest possible value?

Try it

Chapter 07

Investigating calculators

In Understand you met two kinds of calculator. Now test them like a scientist. For each key sequence below, predict what a basic (step-by-step) calculator shows and what a scientific calculator shows, then check if you can.

The basic calculator works like reading a sentence: it finishes each operation before starting the next, and it has no brackets. The scientific calculator waits for = and follows the order of operations.

TableBasic versus scientific: key sequences tested
Keys pressed (then =)Basic showsScientific showsAgree?
2 + 3 × 42014no
20 − 4 × 3488no
10 − 3 + 299yes
8 ÷ 4 × 244yes
6 + 12 ÷ 3610no
5 × 4 − 2 × 35414no
100 − 10 × 5 + 545555no

Predict first

You have only a basic calculator and want 100 − 10 × 5 + 5. Which key sequence gives the correct value (55)?

Reflect

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Chapter 08

Hitting a target

Now combine everything: signs, brackets and the order of operations. A target puzzle gives you numbers and a target; you must hit the target exactly.

Example: use 3, 5, 7, 2 in this order with any signs and brackets to make 30.

  • 3 × 5 + 7 × 2 = 15 + 14 = 29. Close!
  • (3 + 5 + 7) × 2 = 15 × 2 = 30. ✓
  • 3 × (5 + 7) − 2 × 3? Not allowed: that uses 3 twice.

A good strategy is to work backwards: 30 = 15 × 2, so can the first three numbers make 15? 3 + 5 + 7 = 15. Done.

Lab

Step through target-puzzle solutions and confirm each one really hits its target.

  1. Brackets first. Innermost first: ( ) before [ ].
  2. × and ÷ are equal partners: do them left to right.
  3. + and − are equal partners: do them left to right.

BODMAS or DMAS is just a memory aid. D doesn’t beat M, and A doesn’t beat S. They take turns from left to right.

Expression 1 of 6: tap the operation to do next, or tap an opening bracket.

357)2
Text version of this activity

Six solutions to target puzzles. Step through each to check it:

  • (3 + 5 + 7) × 2 = (8 + 7) × 2 = 15 × 2 = 30
  • (9 − 3) × (2 + 2) = 6 × (2 + 2) = 6 × 4 = 24
  • [6 × (4 − 1)] ÷ 2 + 1 = [6 × 3] ÷ 2 + 1 = 18 ÷ 2 + 1 = 9 + 1 = 10
  • (7 + 5) × (8 − 6) = 12 × (8 − 6) = 12 × 2 = 24
  • [20 − (6 + 4)] × 5 = [20 − 10] × 5 = 10 × 5 = 50
  • (10 + 2) ÷ 3 × 6 = 12 ÷ 3 × 6 = 4 × 6 = 24

Targets: 30, 24, 10, 24, 50 and 24. Several different starting numbers can reach 24: it is a favourite target because it has so many factors.

Need a different angle?

Try it

Chapter 09

Zero and one: the troublemakers

When you test a rule, always include 0 and 1. They behave in special ways, and they are where wrong rules most often seem to work.

  • Multiplying by 1 changes nothing: 7 + 1 × 5 = 7 + 5 = 12, the same as if the × were not there.
  • Multiplying by 0 wipes everything out: 7 + 0 × 5 = 7 + 0 = 7, but (7 + 0) × 5 = 35.
  • Adding or subtracting 0 changes nothing: 9 × 4 − 0 = 36.
  • Dividing by 1 changes nothing: 20 ÷ 1 × 3 = 60.
  • Dividing by 0 is not allowed at all: 5 ÷ (3 − 3) has no value.

A classic trick question is 9 − 9 × 0 + 1. People who go left to right say (0) × 0 + 1 = 1. The rule says 9 − 9 × 0 + 1 = 9 − 0 + 1 = 9 + 1 = 10.

TableZero and one inside expressions
ExpressionStepsValueWatch out
7 + 1 × 57 + 1 × 5 = 7 + 5 = 1212× 1 does nothing
7 + 0 × 57 + 0 × 5 = 7 + 0 = 770 × anything = 0
(7 + 0) × 5(7 + 0) × 5 = 7 × 5 = 3535brackets change it
0 ÷ 4 + 40 ÷ 4 + 4 = 0 + 4 = 440 ÷ 4 = 0 is fine
9 − 9 × 0 + 19 − 9 × 0 + 1 = 9 − 0 + 1 = 9 + 1 = 1010not 1
5 ÷ (3 − 3)5 ÷ 0no valuecannot divide by 0

Predict first

What is 1 + 1 × 0 + 1?

Chapter 10

Cricket statistics: does the order of × and ÷ matter?

A batter's strike rate is the runs scored per 100 balls: runs × 100 ÷ balls. If Shafali scores 45 runs off 30 balls, her strike rate is 45 × 100 ÷ 30 = 4,500 ÷ 30 = 150.

Here is an investigation. The formula could also be written runs ÷ balls × 100 or 100 ÷ balls × runs. Do these always give the same value?

  • 45 ÷ 30 × 100: 45 ÷ 30 = 1½, then 1½ × 100 = 150.
  • 100 ÷ 30 × 45: 100 ÷ 30 = 3⅓, then 3⅓ × 45 = 150.

Same value! Each ÷ stays attached to its own number (30), so moving the × and ÷ around does not change the answer. But look at the path: only the first order kept every step a whole number. When you work by hand, multiply first and divide last to avoid fractions along the way.

TableStrike rate three ways (runs × 100 ÷ balls)
Runs, ballsruns × 100 ÷ ballsruns ÷ balls × 100All steps whole?
45, 304,500 ÷ 30 = 1503/2 × 100 = 150only the first way
60, 406,000 ÷ 40 = 1503/2 × 100 = 150only the first way
36, 243,600 ÷ 24 = 1503/2 × 100 = 150only the first way
80, 508,000 ÷ 50 = 1608/5 × 100 = 160only the first way
100, 8010,000 ÷ 80 = 1255/4 × 100 = 125only the first way

Predict first

A bowler's economy rate is runs given ÷ overs. Which expression gives the economy for 42 runs in 6 overs and 30 runs in 4 overs combined?

Try it

Try it

Chapter 11

Splitting a bill: where do the brackets go?

Four friends eat at a dhaba. The bill is ₹640 for food, plus ₹80 for drinks that only two of them had. How much should each person pay?

This is a real investigation, because there are several fair answers, and each is a different expression:

  • Everyone shares everything: (640 + 80) ÷ 4 = (640 + 80) ÷ 4 = 720 ÷ 4 = 180 each.
  • Food shared by all, drinks by the two drinkers: non-drinkers pay 640 ÷ 4 = 160; drinkers pay 640 ÷ 4 + 80 ÷ 2 = 640 ÷ 4 + 80 ÷ 2 = 160 + 80 ÷ 2 = 160 + 40 = 200.
  • Check the second plan adds up: 2 × 160 + 2 × 200 = 2 × 160 + 2 × 200 = 320 + 2 × 200 = 320 + 400 = 720 = 640 + 80 ✓.

The common wrong expression is 640 + 80 ÷ 4 = 640 + 20 = 660 per person, which charges everyone almost the whole bill! The ÷ grabbed only the 80.

Explore

Four ways to split a ₹720 dhaba bill

Choose a rule for sharing and see its expression.

  1. Add food and drinks
  2. (640 + 80)
  3. Share by 4
  4. ₹180 each

Brackets needed

(640 + 80) ÷ 4 = 720 ÷ 4 = 180. Simple and quick; the two who did not have drinks pay ₹20 more than their share of what they ate and drank.

Predict first

Six friends share a ₹900 bill equally, but one friend has a ₹150 discount coupon that applies to the whole bill. Which expression gives each person's share?

Try it

Worked example

0 / 5 steps shown

When does a missing bracket not matter?

An auto fare is ₹30 to start plus ₹15 per km: 30 + 15 × km. A careless app programmer writes (30 + 15) × km instead. For which trip lengths does the app still charge the right fare?

Try it

Reflect

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Chapter 12

Spreadsheet experiments

A spreadsheet is a perfect laboratory for the order of operations: type a formula, press Enter, and the machine shows exactly how it reads it. Try this experiment (or predict the results if you have no computer to hand). Put 10 in A1, 4 in A2 and 2 in A3. Then type each formula into a new cell and predict before you press Enter.

TablePredict, then test: A1 = 10, A2 = 4, A3 = 2
FormulaMeansResult
=A1-A2+A310 − 4 + 28
=A1-(A2+A3)10 − (4 + 2)4
=A1/A3*A210 ÷ 2 × 420
=A1/(A3*A2)10 ÷ (2 × 4)5/4 (shown as 1.25)
=A1+A2*A310 + 4 × 218
=(A1+A2)*A3(10 + 4) × 228
=(A1+A2+A3)/3(10 + 4 + 2) ÷ 316/3 (shown as 5.33)
=A1+A2+A3/310 + 4 + 2 ÷ 344/3 (shown as 14.67)

Predict first

With A1 = 10, A2 = 4 and A3 = 2, what does =A1*A2/A3-A2 give?

Worked example

0 / 4 steps shown

Testing a GST column

A shop's spreadsheet has prices in column B and needs the price with 18% GST in column C. Someone types =B2+B2*18/100 and someone else **=(B2+B2)18/100*. Test both with B2 = 500.

Try it

A shop spreadsheet should give the average of three prices in C2, C3, C4, but shows a number bigger than all three. The formula is =C2+C3+C4/3. Which is the fix?

Chapter 13

What you found out

Words for investigating

Conjecture
A statement you think is true, based on examples, but have not yet proved.
Example: Removing a bracket after − flips the signs inside.
Counterexample
One example that shows a statement is not always true.
Example: (20 − 8) − 2 = 10 but 20 − (8 − 2) = 14.
Associative
An operation is associative if grouping does not matter: (a ∘ b) ∘ c = a ∘ (b ∘ c). + and × are; − and ÷ are not.
Example: (2 × 3) × 4 = 2 × (3 × 4)
Bracketing
A way of placing brackets in an expression to fix the order.
Example: (2 + 3) × (4 − 1)
Fully bracketed
Every operation has its own pair of brackets, so no rule is needed to read it.
Example: ((2 + 3) × 4) − 1
Catalan numbers
1, 2, 5, 14, 42, 132, … The number of ways to fully bracket 2, 3, 4, 5, 6, 7, … numbers.
Target puzzle
A puzzle where numbers must be combined with operations to reach an exact value.
Example: Make 24 from 7, 5, 8, 6.

Quick check

Investigation check-up

9 questions · answer what you can, then check. Getting one wrong is useful.

  1. Q1How many different values can brackets give 2 + 3 × 4 − 1 (order kept)?
  2. Q2Which operation is associative?
  3. Q3100 − (40 − 15) equals…
  4. Q4Is "a + b × c = (a + b) × c" always, sometimes or never true?
  5. Q5A basic calculator and a scientific one will always agree on…
  6. Q6Using 1, 2, 3, 4 once each with + and × and brackets, the biggest value is…
  7. Q7Which filling of 6 ▢ 3 ▢ 2 gives 0?
  8. Q8How many ways are there to fully bracket 5 numbers?
  9. Q9What is enough to show a statement is NOT always true?

Keep this

Cheat sheet

  • Moving brackets can change the value: 2 + 3 × 4 − 1 can be 11, 13, 15 or 19. Four numbers can be fully bracketed in 5 ways; five numbers in 14 (Catalan numbers).
  • Free brackets: brackets change nothing when they surround what the rule does first anyway, or when only + or only × is involved (associative).
  • − and ÷ are not associative: (20 − 8) − 2 = 10 but 20 − (8 − 2) = 14. That is why partners go left to right.
  • Opening brackets: after −, flip + and − inside; after ÷, flip × and ÷ inside. After + (or × with only × ÷ inside) nothing flips.
  • Always / sometimes / never: one counterexample kills "always"; a reason is needed to prove "always".
  • Missing signs: 6 ▢ 3 ▢ 2 has 16 fillings; the order of operations decides each value.
  • Biggest values: multiply numbers above 2, add 1s. (1 + 2) × 3 × 4 = 36.
  • Calculators: basic and scientific agree unless a + or − comes before a × or ÷.
  • Targets: work backwards from the target: 30 = 15 × 2, so make 15 from the rest.

Helps you understand

Properties of numbers

Associativity and the distributive property, tested here with brackets, are studied in Properties of numbers.

Related to

Number and shape patterns

Counting bracketings gives the Catalan numbers 1, 2, 5, 14, 42, a number pattern with its own rule.

Used in

Data handling

The mean is (sum of values) ÷ (number of values). Forgetting the brackets and dividing only the last value is a classic slip.

Where this comes from

Sources

End of Investigate

What you just read

  • Find all the values an expression can take when brackets are moved, and explain why four numbers have five bracketings.
  • Decide when brackets change a value, using associativity and the order of operations.
  • Test conjectures about removing brackets after − and ÷, and use counterexamples.
  • Predict what basic and scientific calculators show for a key sequence.
  • Solve missing-sign and target puzzles by reasoning and working backwards.

The web

Explore a connection

  • Builds on

    Properties of numbers

    The distributive property explains why multiplication is done before addition and how brackets change a result.

  • Builds on

    Four operations

    Once each operation is reliable, the next question is which one to do first when several appear together.

  • Related to

    Number and shape patterns

    A pattern rule such as 3 × n + 1 is an expression — you need the order of operations to use it.

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Revision 1 · release preview-7e1cbbcc4f · accepted 20/09/2026